创建目录中多个文本文件的字数统计字典

我在 word_count_directory() 函数中使用 build_dict() 函数来创建目录中三个文件的字数统计字典。我想创建三个字典（每个文件一次一个）并更新以前的字典。我的代码创建一个字典（word_count），它同时组合所有三个字典。我想知道如何实现这一点？

def build_dict(filename):
   f = open(filename, 'rU')
   words = f.read().split()
   count = {}

   for word in words:
      word = word.lower()
      if word not in count:
        count[word] = 1
      else:
        count[word] += 1

   f.close()

   return count
## print build_dict("C:\\Users\\Phil2040\\Desktop\\word_count\\news1.txt")

import os
import os.path
def word_count_directory(directory):
    wordcount={}
    filelist=[os.path.join(directory,f) for f in os.listdir(directory)]
    for file in filelist:
       wordcount=build_dict(file)  # calling build_dict function
    return wordcount
print word_count_directory("C:\\Users\\Phil2040\\Desktop\\Word_count")

Use collections.Counter https://docs.python.org/2/library/collections.html#collections.Counter.

示例文件：

/tmp/foo.txt

hello world
hello world
foo bar
foo bar baz

/tmp/bar.txt

hello world
hello world
foo bar
foo bar baz
foo foo foo

您可以创建一个Counter每个文件，然后将它们添加在一起！

from collections import Counter

def word_count(filename):
    with open(filename, 'r') as f:
        c = Counter()
        for line in f:
            c.update(line.strip().split(' '))
        return c

files = ['/tmp/foo.txt', '/tmp/bar.txt']
counters = [word_count(filename) for filename in files]

# counters content (example):
# [Counter({'world': 2, 'foo': 2, 'bar': 2, 'hello': 2, 'baz': 1}),
#  Counter({'foo': 5, 'world': 2, 'bar': 2, 'hello': 2, 'baz': 1})]

# Add all the word counts together:
total = sum(counters, Counter())  # sum needs an empty counter to start with

# total content (example):
# Counter({'foo': 7, 'world': 4, 'bar': 4, 'hello': 4, 'baz': 2})