如何通过直接修改IDENTIFY数据包来获取discord bot的移动状态？

显然，discord 机器人可以具有移动状态，而不是默认获得的桌面（在线）状态。

经过一番挖掘后，我发现这种状态是通过修改IDENTIFY packet in discord.gateway.DiscordWebSocket.identify https://github.com/Rapptz/discord.py/blob/45d498c1b76deaf3b394d17ccf56112fa691d160/discord/gateway.py#L370修改值$browser to Discord Android or Discord iOS理论上应该让我们获得移动状态。

修改我在网上找到的执行此操作的代码片段后，我最终得到以下结果：

def get_mobile():
    """
    The Gateway's IDENTIFY packet contains a properties field, containing $os, $browser and $device fields.
    Discord uses that information to know when your phone client and only your phone client has connected to Discord,
    from there they send the extended presence object.
    The exact field that is checked is the $browser field. If it's set to Discord Android on desktop,
    the mobile indicator is is triggered by the desktop client. If it's set to Discord Client on mobile,
    the mobile indicator is not triggered by the mobile client.
    The specific values for the $os, $browser, and $device fields are can change from time to time.
    """
    import ast
    import inspect
    import re
    import discord

    def source(o):
        s = inspect.getsource(o).split("\n")
        indent = len(s[0]) - len(s[0].lstrip())

        return "\n".join(i[indent:] for i in s)

    source_ = source(discord.gateway.DiscordWebSocket.identify)
    patched = re.sub(
        r'([\'"]\$browser[\'"]:\s?[\'"]).+([\'"])',
        r"\1Discord Android\2",
        source_,
    )

    loc = {}
    exec(compile(ast.parse(patched), "<string>", "exec"), discord.gateway.__dict__, loc)
    return loc["identify"]

现在剩下要做的就是覆盖discord.gateway.DiscordWebSocket.identify在主文件的运行时，类似这样的内容：

import discord
import os
from discord.ext import commands
import mobile_status

discord.gateway.DiscordWebSocket.identify = mobile_status.get_mobile()
bot = commands.Bot(command_prefix="?")

@bot.event
async def on_ready():
    print(f"Sucessfully logged in as {bot.user}")

bot.run(os.getenv("DISCORD_TOKEN"))

And we do get the mobile status successfully

但这是问题所在，我想直接修改该文件（包含该函数），而不是在运行时对其进行猴子修补。所以我在本地克隆了 dpy lib 并在我的机器上编辑了该文件，它最终看起来像这样：

    async def identify(self):
        """Sends the IDENTIFY packet."""
        payload = {
            'op': self.IDENTIFY,
            'd': {
                'token': self.token,
                'properties': {
                    '$os': sys.platform,
                    '$browser': 'Discord Android',
                    '$device': 'Discord Android',
                    '$referrer': '',
                    '$referring_domain': ''
                },
                'compress': True,
                'large_threshold': 250,
                'v': 3
            }
        }
     # ...

（编辑了两者$browser and $device to Discord Android只是为了安全起见）

但这不起作用，只是给了我常规的桌面在线图标。
所以我接下来要做的就是检查identify功能after它已经被猴子修补了，所以我可以查看源代码，看看之前出了什么问题，但由于运气不好，我得到了这个错误：

Traceback (most recent call last):
  File "c:\Users\Achxy\Desktop\fresh\file.py", line 8, in <module>
    print(inspect.getsource(discord.gateway.DiscordWebSocket.identify))
  File "C:\Users\Achxy\AppData\Local\Programs\Python\Python39\lib\inspect.py", line 1024, in getsource
    lines, lnum = getsourcelines(object)
  File "C:\Users\Achxy\AppData\Local\Programs\Python\Python39\lib\inspect.py", line 1006, in getsourcelines
    lines, lnum = findsource(object)
  File "C:\Users\Achxy\AppData\Local\Programs\Python\Python39\lib\inspect.py", line 835, in findsource
    raise OSError('could not get source code')
OSError: could not get source code

Code :

import discord
import os
from discord.ext import commands
import mobile_status
import inspect

discord.gateway.DiscordWebSocket.identify = mobile_status.get_mobile()
print(inspect.getsource(discord.gateway.DiscordWebSocket.identify))
bot = commands.Bot(command_prefix="?")

@bot.event
async def on_ready():
    print(f"Sucessfully logged in as {bot.user}")

bot.run(os.getenv("DISCORD_TOKEN"))

由于每个修补函数都表现出相同的行为（上述函数和loc["identify"]）我无法再使用inspect.getsource(...)然后依靠dis.dis这导致了更令人失望的结果

反汇编的数据看起来与猴子补丁的工作版本完全相同，因此尽管功能内容完全相同，但直接修改的版本根本无法工作。 （关于拆解数据）

备注：做Discord iOS直接也不起作用，改变$device到其他一些值，但保持$browser不起作用，我已经尝试了所有组合，但没有一个起作用。

TL;DR：如何在运行时不对其进行猴子修补的情况下获取不和谐机器人的移动状态？

DiscordWebSocket.identify非常重要，并且没有受支持的方法来覆盖这些字段。

复制粘贴 35* 行代码来修改 2 行代码的更可维护的替代方法是子类化，然后覆盖DiscordWebSocket.send_as_json（4行自定义代码），并修补classmethod DiscordWebSocket.from_client实例化子类：

import os

from discord.ext import commands
from discord.gateway import DiscordWebSocket


class MyDiscordWebSocket(DiscordWebSocket):

    async def send_as_json(self, data):
        if data.get('op') == self.IDENTIFY:
            if data.get('d', {}).get('properties', {}).get('$browser') is not None:
                data['d']['properties']['$browser'] = 'Discord Android'
                data['d']['properties']['$device'] = 'Discord Android'
        await super().send_as_json(data)


DiscordWebSocket.from_client = MyDiscordWebSocket.from_client
bot = commands.Bot(command_prefix="?")


@bot.event
async def on_ready():
    print(f"Sucessfully logged in as {bot.user}")

bot.run(os.getenv("DISCORD_TOKEN"))

*Pycord 1.7.3 中的 39 行。通过覆盖，您通常无需额外的努力即可获得未来的更新。