如何用OpenCV绘制圆角矩形（带圆角的矩形）？

如何在 OpenCV 中绘制圆角矩形？我知道函数 ellipse() 和 line() 可以简单地放在一起来绘制它。我只是想知道是否有人以前做过并将其放入适当的函数中以便我可以使用它？理想情况下，拐角半径是在参数中校准的。

我搜索了很多，但似乎以前没有人遇到过这个问题。如果没有人有这样的功能，我可能会在几天后在这里发布我自己的解决方案。

我意识到，这比我想象的要容易得多。这是我的功能。我希望它对某人有帮助。

/**
 * Draws a rectangle with rounded corners, the parameters are the same as in the OpenCV function @see rectangle();
 * @param cornerRadius A positive int value defining the radius of the round corners.
 * @author K
 */
void rounded_rectangle( Mat& src, Point topLeft, Point bottomRight, const Scalar lineColor, const int thickness, const int lineType , const int cornerRadius)
{
    /* corners:
     * p1 - p2
     * |     |
     * p4 - p3
     */
    Point p1 = topLeft;
    Point p2 = Point (bottomRight.x, topLeft.y);
    Point p3 = bottomRight;
    Point p4 = Point (topLeft.x, bottomRight.y);
    
    // draw straight lines
    line(src, Point (p1.x + cornerRadius, p1.y), Point (p2.x - cornerRadius, p2.y), lineColor, thickness, lineType);
    line(src, Point (p2.x, p2.y + cornerRadius), Point (p3.x, p3.y - cornerRadius), lineColor, thickness, lineType);
    line(src, Point (p4.x + cornerRadius, p4.y), Point (p3.x-cornerRadius, p3.y), lineColor, thickness, lineType);
    line(src, Point (p1.x, p1.y + cornerRadius), Point (p4.x, p4.y - cornerRadius), lineColor, thickness, lineType);
    
    // draw arcs
    ellipse( src, p1 + Point(cornerRadius, cornerRadius), Size( cornerRadius, cornerRadius ), 180.0, 0, 90, lineColor, thickness, lineType );
    ellipse( src, p2 + Point(-cornerRadius, cornerRadius), Size( cornerRadius, cornerRadius ), 270.0, 0, 90, lineColor, thickness, lineType );
    ellipse( src, p3 + Point(-cornerRadius, -cornerRadius), Size( cornerRadius, cornerRadius ), 0.0, 0, 90, lineColor, thickness, lineType );
    ellipse( src, p4 + Point(cornerRadius, -cornerRadius), Size( cornerRadius, cornerRadius ), 90.0, 0, 90, lineColor, thickness, lineType );
}