将big.Float转换为big.Int,我在下面编写代码,但它溢出了uint64,那么将big.Float转换为big.Int的正确方法是什么。
package main
import "fmt"
import "math/big"
func FloatToBigInt(val float64) *big.Int {
bigval := new(big.Float)
bigval.SetFloat64(val)
coin := new(big.Float)
coin.SetInt(big.NewInt(1000000000000000000))
bigval.Mul(bigval, coin)
result := new(big.Int)
f,_ := bigval.Uint64()
result.SetUint64(f)
return result
}
func main() {
fmt.Println("vim-go")
fmt.Println(FloatToBigInt(float64(10)))
fmt.Println(FloatToBigInt(float64(20)))
fmt.Println(FloatToBigInt(float64(30)))
fmt.Println(FloatToBigInt(float64(40)))
fmt.Println(FloatToBigInt(float64(50)))
fmt.Println(FloatToBigInt(float64(100)))
fmt.Println(FloatToBigInt(float64(1000)))
fmt.Println(FloatToBigInt(float64(10000)))
}
一个大整数大于uint64
总是会导致溢出uint64
有固定大小。您应该使用以下内容method https://golang.org/pkg/math/big/#Float.Int on *Float
:
func (*Float) Int
所需的更改是:
func FloatToBigInt(val float64) *big.Int {
bigval := new(big.Float)
bigval.SetFloat64(val)
// Set precision if required.
// bigval.SetPrec(64)
coin := new(big.Float)
coin.SetInt(big.NewInt(1000000000000000000))
bigval.Mul(bigval, coin)
result := new(big.Int)
bigval.Int(result) // store converted number in result
return result
}
工作示例:https://play.golang.org/p/sEhH6iPkrK https://play.golang.org/p/sEhH6iPkrK
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