如何正确调用 LsaLogonUser 进行交互式登录？

我正在尝试使用 LsaLogonUser 创建交互式登录会话，但它总是返回STATUS_INVALID_INFO_CLASS（0xc0000003）。从网上查到的内存布局KERB_INTERACTIVE_LOGON结构很棘手，但我很确定我做得对。

我还尝试过使用 MSV1.0 而不是 Kerberos，MSV1_0_INTERACTIVE_LOGON对于认证结构和MSV1_0_PACKAGE_NAME作为包名称，但是失败了STATUS_BAD_VALIDATION_CLASS（0xc00000a7）。

谁能告诉我我在这里做错了什么？这是代码，其中删除了大部分错误处理。显然，这不是生产质量；而是质量。我只是想得到一个工作样本。

// see below for definitions of these
size_t wcsByteLen( const wchar_t* str );
void InitUnicodeString( UNICODE_STRING& str, const wchar_t* value, BYTE* buffer, size_t& offset );

int main( int argc, char * argv[] )
{
    // connect to the LSA
    HANDLE lsa;
    LsaConnectUntrusted( &lsa; );

    const wchar_t* domain = L"mydomain";
    const wchar_t* user = L"someuser";
    const wchar_t* password = L"scaryplaintextpassword";

    // prepare the authentication info
    ULONG authInfoSize = sizeof(KERB_INTERACTIVE_LOGON) +
     wcsByteLen( domain ) + wcsByteLen( user ) + wcsByteLen( password );
    BYTE* authInfoBuf = new BYTE[authInfoSize];
    KERB_INTERACTIVE_LOGON* authInfo = (KERB_INTERACTIVE_LOGON*)authInfoBuf;
    authInfo->MessageType = KerbInteractiveLogon;
    size_t offset = sizeof(KERB_INTERACTIVE_LOGON);
    InitUnicodeString( authInfo->LogonDomainName, domain, authInfoBuf, offset );
    InitUnicodeString( authInfo->UserName, user, authInfoBuf, offset );
    InitUnicodeString( authInfo->Password, password, authInfoBuf, offset );

    // find the Kerberos security package
    char packageNameRaw[] = MICROSOFT_KERBEROS_NAME_A;
    LSA_STRING packageName;
    packageName.Buffer = packageNameRaw;
    packageName.Length = packageName.MaximumLength = (USHORT)strlen( packageName.Buffer );
    ULONG packageId;
    LsaLookupAuthenticationPackage( lsa, &packageName;, &packageId; );

    // create a dummy origin and token source
    LSA_STRING origin = {};
    origin.Buffer = _strdup( "TestAppFoo" );
    origin.Length = (USHORT)strlen( origin.Buffer );
    origin.MaximumLength = origin.Length;
    TOKEN_SOURCE source = {};
    strcpy( source.SourceName, "foobar" );
    AllocateLocallyUniqueId( &source.SourceIdentifier; );

    void* profileBuffer;
    DWORD profileBufLen;
    LUID luid;
    HANDLE token;
    QUOTA_LIMITS qlimits;
    NTSTATUS subStatus;
    NTSTATUS status = LsaLogonUser( lsa, &origin;, Interactive, packageId,
     &authInfo;, authInfoSize, 0, &source;, &profileBuffer;, &profileBufLen;,
     &luid;, &token;, &qlimits;, &subStatus; );
    if( status != ERROR_SUCCESS )
    {
        ULONG err = LsaNtStatusToWinError( status );
        printf( "LsaLogonUser failed: %x\n", status );
        return 1;
    }
}

size_t wcsByteLen( const wchar_t* str )
{
    return wcslen( str ) * sizeof(wchar_t);
}

void InitUnicodeString( UNICODE_STRING& str, const wchar_t* value,
 BYTE* buffer, size_t& offset )
{
    size_t size = wcsByteLen( value );
    str.Length = str.MaximumLength = (USHORT)size;
    str.Buffer = (PWSTR)(buffer + offset);
    memcpy( str.Buffer, value, size );
    offset += size;
}

您搞砸了 LsaLogonUser() 的参数之一；代替&authInfo你应该通过authInfo。每个人都会发生:)