如何按时间字符串值对对象数组进行排序？

我有一个像这样的对象数组：

var example = [{
  "description": "aaa",
  "time": "12:15pm"
}, {
  "description": "bbb",
  "time": "10:10am"
}, {
  "description": "ccc",
  "time": "4:00pm"
}, {
  "description": "ddd",
  "time": "6:15pm"
}, {
  "description": "eee",
  "time": "1:10am"
}, {
  "description": "fff",
  "time": "5:00pm"
} ];

我想按time价值。

我已尝试申请这个解决方案 https://stackoverflow.com/a/17064665/1063287这是用于字符串值数组的：

example.sort(function (a, b) {
  return new Date('1970/01/01 ' + a.time) - new Date('1970/01/01 ' + b.time);
});

console.log(example);

我也提到过 MozillaArray.prototype.sort() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort文档并尝试了以下似乎不起作用的方法：

example.sort(function(a, b) {
  if (new Date(a.time) > new Date(b.time)) {
    return 1;
  }
  if (new Date(a.time) < new Date(b.time)) {
    return -1;
  }
  // a must be equal to b
  return 0;
});

console.log(example);

您生成的日期字符串无效，因此它将始终返回当前日期和时间。因此生成有效的日期字符串（例如：'1970/01/01 9:34:48 AM'）然后解析并返回差异。这里String#slice() https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/slice方法可用于生成有效的日期字符串。

var example = [{
  "description": "aaa",
  "time": "12:15pm"
}, {
  "description": "bbb",
  "time": "10:10am"
}, {
  "description": "ccc",
  "time": "4:00pm"
}, {
  "description": "ddd",
  "time": "6:15pm"
}, {
  "description": "eee",
  "time": "1:10am"
}, {
  "description": "fff",
  "time": "5:00pm"
}];

example.sort(function(a, b) {
  // get time from string 
  // then get am or pm from string and append
  // both can be done using the slice method
  return Date.parse('1970/01/01 ' + a.time.slice(0, -2) + ' ' + a.time.slice(-2)) - Date.parse('1970/01/01 ' + b.time.slice(0, -2) + ' ' + b.time.slice(-2))
});

console.log(example);