HttpWebRequest request = null;
WebResponse response = null;
try
{
string myURL = "https://blah.blah.gov/themagicform.cfm"; //The URL for my requests:
request = (HttpWebRequest)WebRequest.Create(myURL); // Create a request using a URL that can receive a post.
request.Credentials = new NetworkCredential("MyUserName", "MyPassWord"); //The credentials for the website.
request.Method = "POST"; // Set the Method property of the request to POST.
//request.ContentType = "text/xml"; // Set the ContentType property of the WebRequest.
request.ContentType = "application/x-www-form-urlencoded";
// Specify Headers
request.Headers.Add("HTTP_HOST", "MyZone");
request.Headers.Add("HTTP_USER_AGENT", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.1.4322)");
request.Headers.Add("HTTP_ACCEPT", "text/xml");
StreamWriter writer = new StreamWriter(request.GetRequestStream()); // Wrap the request stream with a text-based writer
writer.WriteLine(XMLDoc); // Write the xml text into the stream
writer.Close();
/* Previously I tried:
string postData = XMLDoc; // Create POST data and convert it to a byte array.
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
request.ContentLength = byteArray.Length; // Set the ContentLength property of the WebRequest.
Stream dataStream = request.GetRequestStream(); // Get the request stream.
dataStream.Write(byteArray, 0, byteArray.Length); // Write the data to the request stream.
dataStream.Close(); // Close the Stream object - which submits the "form" data.
*/
Stream dataStream = null;
// Send the data to the webserver
response = request.GetResponse(); // Get the response.
lbl_ResponseInfo.Text = ((HttpWebResponse)response).StatusDescription.ToString(); // Display the status.
dataStream = response.GetResponseStream(); // Get the stream containing content returned by the server.
StreamReader incomingStreamReader = new StreamReader(dataStream); // Open the stream using a StreamReader for easy access.
string responseFromServer = incomingStreamReader.ReadToEnd();// Read the content.
// Display the content. XMLResponse is a special type of label on my asp page
XMLResponse.Visible = true;
XMLResponse.TransformSource = "defaultss.xslt";
XMLResponse.DocumentContent = responseFromServer;
lbl_Received.Visible = true;
// Clean up the streams.
incomingStreamReader.Close();
dataStream.Close();
response.Close();
//Display the XML we sent
XMLSent.Visible = true;
XMLSent.TransformSource = "defaultss.xslt";
XMLSent.DocumentContent = XMLDoc;
lbl_Sent.Visible = true;
}
catch (WebException webEx)
{
lbl_ResponseInfo.Text = webEx.Message.ToString();
}
catch (Exception ex)
{
lbl_ResponseInfo.Text = ex.Message.ToString();
}
finally
{
if (request != null) request.GetRequestStream().Close();
if (response != null) response.GetResponseStream().Close();
}