编程每日一题_C程序设计_日K蜡烛图

描述：

来源： pintia

正确解法一：

//嵌套 if 条件判断
#include<stdio.h>

int main()
{
	float Open,High,Low,Close;
	
	scanf("%f %f %f %f",&Open,&High,&Low,&Close);
	
	if (Close<Open){
		if(Low<Close){
			if (High>Open){
				printf("BW-Solid with Lower Shadow and Upper Shadow\n");
			} else printf("BW-Solid with Lower Shadow\n");
		} else if (High>Open){
			printf("BW-Solid with Upper Shadow\n");
		}else printf("BW-Solid");
	} else if(Close==Open){
		if (Low<Close){
			if (High>Close){
				printf("R-Cross with Lower Shadow and Upper Shadow\n");
			}else printf("R-Cross with Lower Shadow\n");
		} else if (High>Close) {
			printf("R-Cross with Upper Shadow\n");
		}else printf("R-Cross\n");
	} else if (Low<Open){
		if (High>Close){
			printf("R-Hollow with Lower Shadow and Upper Shadow\n");
		}else printf("R-Hollow with Lower Shadow\n");
	}else if (High>Close){
		printf("R-Hollow with Upper Shadow\n");
	}else printf("R-Hollow\n");
	return 0;
 }

解法二：

//参考来源：https://blog.csdn.net/qq_32999795/article/details/53750065
 #include<stdio.h>
int main()
{
    double open,close,high,low;
    scanf("%lf %lf %lf %lf",&open,&high,&low,&close);

    {
        if(close<open)
        printf("BW-Solid");
    else if(close>open)
        printf("R-Hollow");
    else
        printf("R-Cross");
    }

    {//上下影线都存在的情况，记得加上前面的空格
    if((low<open&&low<close)&&(high>open&&high>close))
        printf(" with Lower Shadow and Upper Shadow");
     //下影线
    else if(low<open&&low<close)
        printf(" with Lower Shadow");
    //上影线
    else if(high>open&&high>close)
        printf(" with Upper Shadow");

    }
        return 0;
}