PAT A1153

题目：https://pintia.cn/problem-sets/994805342720868352/problems/1071785190929788928

这道题我很久才AC，主要是不知道原来它的输入可以乱来。我原先是单独用scanf接收flag，然后再分三种情况接收后面的东西，即flag==1，接收%c；flag==2或flag==3都是用%d接收。结果一直有两个答案是错的。思考了很久觉得逻辑没有错，就只有考虑输入的东西奇形怪状，于是直接把输入整个接收，然后分情况，最后就AC了

#include <cstdio>
#include <iostream>
#include <string>
#include <cstring>
#include <algorithm>
#include <vector>
using namespace std;
const int maxn = 10010;
int n, m;
vector<int> A, B, T;
int nt[1010] = {0}, ns[1010] = {0};
int vis[1010];

struct Node{
	string cardnum;
	int score, site;
}node[maxn];

int change(string a, int Left, int Right){
	int num = 0;
	for(int i = Left; i <= Right; i++)
		num = num * 10 + a[i] - '0';
	return num;
}

bool cmp1(int a, int b){
	if(node[a].score != node[b].score)
		return node[a].score > node[b].score;
	else
		return node[a].cardnum < node[b].cardnum;
}

bool cmp2(int a, int b){
	if(vis[node[a].site] != vis[node[b].site])
		return vis[node[a].site] > vis[node[b].site];
	else
		return node[a].site < node[b].site;
}

int main(){
	scanf("%d%d", &n, &m);
	getchar();
	for(int i = 0; i < n; i++){
		cin>>node[i].cardnum>>node[i].score;
		if(node[i].cardnum[0] == 'B')
			B.push_back(i);
		else if(node[i].cardnum[0] == 'A')
			A.push_back(i);
		else
			T.push_back(i);
		int site = change(node[i].cardnum, 1, 3);
		node[i].site = site;
		++nt[site];
		ns[site] += node[i].score;
	}
	sort(A.begin(), A.end(), cmp1);
	sort(B.begin(), B.end(), cmp1);
	sort(T.begin(), T.end(), cmp1);
	for(int i = 1; i <= m; ++i){
		int flag;
		string str;
		cin>>flag>>str;
		cout<<"Case "<<i<<": "<<flag<<" "<<str<<endl;
		if(flag == 1){
			vector<int> ans;
			if(str == "B")
				ans = B;
			else if(str == "A")
				ans = A;
			else if(str == "T")
				ans = T;
			if(ans.empty()){
				printf("NA\n");
				continue;
			}
			for(int k = 0; k < ans.size(); k++)
				cout<<node[ans[k]].cardnum<<" "<<node[ans[k]].score<<endl;
			
		}else if(flag == 2){
			int site;
			sscanf(str.c_str(), "%d", &site);
			if(nt[site])
				printf("%d %d\n", nt[site], ns[site]);
			else
				printf("NA\n");
		}else{
			vector<int> ans;
			fill(vis, vis+1010, 0);
			for(int j = 0; j < n; j++){
				if(node[j].cardnum.substr(4, 6) == str){
					if(!vis[node[j].site]){
						ans.push_back(j);
					}
					vis[node[j].site]++;
				}
			}
			sort(ans.begin(), ans.end(), cmp2);
			if(ans.empty())
				printf("NA\n");
			for(int j = 0; j < ans.size(); j++){
				printf("%d %d\n", node[ans[j]].site, vis[node[ans[j]].site]);
			}
		}
	}
	return 0;
}