由于工作中经常用到关于用户自定义时间，来进行后台数据的查询，特意整理了一下工作中常用的到的关于时间列表的一个函数，可以计算出某一年中的具体哪个周的开始和结束日期，某个周的具体日期列表（2015年38周），自定义时间段的具体日期列表（20150901-20151010）
1、计算周的日期函数。包含某一周开始、结束日期，某一周的详细日期列表
import datetime
def allweeks(week):
"计算一年内所有周的具体日期"
_week = int(week)-1
current = datetime.datetime.now()
start = datetime.date(current.year,1,1)
last_day = datetime.date(current.year,12,31)
isfirst = start.weekday()
last_week = last_day.strftime('%W')
weeks={} #计算出一年中每个周的开始和结束日期。例如：0: [datetime.date(2015, 1, 1), datetime.date(2015, 1, 4)]
date_list_for_week = [] #用于得出具体的某一个周的具体天数列表：例如: 第9周：['20150223', '20150224', '20150225', '20150226', '20150227', '20150228', '20150301']
if isfirst !=0:
end = datetime.timedelta(7-start.weekday()-1)
weeks[0]=[start,start+end]
start += datetime.timedelta(7 - start.weekday())
for i in range(0,int(last_week)):
days = datetime.timedelta(weeks=i)
end = start + days
if i+1 == int(last_week):
weeks[i+1] = [end,last_day]
else:
weeks[i+1] = [end,end + datetime.timedelta(6)]
starttime = ''.join(str(weeks[_week][0]).split('-'))#计算出给出周的开始日期，如20150907
endtime = ''.join(str(weeks[_week][1]).split("-"))#计算出给出周的结束日期，如201509013
delta = datetime.timedelta(days=1)
startdate = datetime.datetime(int(starttime[0:4]),int(starttime[4:6]),int(starttime[6:8]))
if int(starttime[4:6]) == int(endtime[4:6]):
for i in range(int(endtime[6:]) - int(starttime[6:])+1):
days = (startdate +delta*i).strftime('%Y%m%d')
date_list_for_week.append(days)
elif int(starttime[4:6]) != int(endtime[4:6]):
for i in range(7):
days = (startdate +delta*i).strftime('%Y%m%d')
date_list_for_week.append(days)
return date_list_for_week,weeks,starttime,endtime
if __name__ == "__main__":
week =9
print allweeks(week)
2、计算自定义时间的日期函数。（比如计算20150811-20150922之间的日期列表）
import datetime
def get_yestoday(starttime,endtime):
startdate = datetime.datetime(int(starttime[0:4]),int(starttime[4:6]),int(starttime[6:8]))
#now = datetime.datetime.now()
delta = datetime.timedelta(days=1)
# my_yestoday = startdate + delta
# my_yes_time = my_yestoday.strftime('%Y%m%d')
n = 0
date_list = []
while 1:
if starttime<=endtime:
days = (startdate + delta*n).strftime('%Y%m%d')
n = n+1
date_list.append(days)
if days == endtime:
break
return date_list
print get_yestoday('20150811','20150922')
