题目
![在这里插入图片描述](https://img-blog.csdnimg.cn/58f609a53cd64c86a489a6589b78b42f.png)
思路
维护两个栈,一个栈正常push元素,另一个栈维护每个元素为栈顶元素时的最小栈元素值。
stack1.push(x);
val = x < minStack.top()?x:minStack.top();
题解
class MinStack {
stack<int> minStack;
stack<int> stack1;
int val = INT_MAX;
public:
MinStack() {
minStack.push(INT_MAX);
}
void push(int x) {
//push元素的时候 也维护当前栈的最小值
stack1.push(x);
val = x < minStack.top()?x:minStack.top();
minStack.push(val);
}
void pop() {
stack1.pop();
minStack.pop();
}
int top() {
return stack1.top();
}
int getMin() {
return minStack.top();
}
};
/**
* Your MinStack object will be instantiated and called as such:
* MinStack* obj = new MinStack();
* obj->push(val);
* obj->pop();
* int param_3 = obj->top();
* int param_4 = obj->getMin();
*/