当线程启动(.start)时,有什么方法可以将参数传递给 QThread 吗?
我在 stackoverflow 中找到了一个使用 pyqt 线程的示例,但我想知道如何传递参数,以防我希望工作线程处理我传递给其 run() 函数的数据。
我参考的帖子:带 PyQt 进度条的忙碌指示
代码:
class MyCustomWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(MyCustomWidget, self).__init__(parent)
layout = QtGui.QVBoxLayout(self)
self.progressBar = QtGui.QProgressBar(self)
self.progressBar.setRange(0,100)
button = QtGui.QPushButton("Start", self)
layout.addWidget(self.progressBar)
layout.addWidget(button)
button.clicked.connect(self.onStart)
self.myLongTask = TaskThread()
self.myLongTask.notifyProgress.connect(self.onProgress)
def onStart(self):
self.myLongTask.start()
def onProgress(self, i):
self.progressBar.setValue(i)
class TaskThread(QtCore.QThread):
notifyProgress = QtCore.pyqtSignal(int)
def run(self):
for i in range(101):
self.notifyProgress.emit(i)
time.sleep(0.1)
我想在调用 .start 时传递一个变量,例如
self.myLongTask.start(myvar)
.
.
def run(self, myvar):
但当然,pyqt 不允许这样做。
您不能将参数传递给run
但您可以将参数传递给它的构造函数,如下所示:
class TaskThread(QtCore.QThread):
notifyProgress = QtCore.pyqtSignal(int)
def __init__(self, myvar, parent=None):
QThread.__init__(self, parent)
self.myvar = myvar
def run(self):
#use self.myvar in your run
for i in range(101):
self.notifyProgress.emit(i)
time.sleep(0.1)
并在MyCustomWidget
class:
class MyCustomWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(MyCustomWidget, self).__init__(parent)
layout = QtGui.QVBoxLayout(self)
self.progressBar = QtGui.QProgressBar(self)
self.progressBar.setRange(0,100)
button = QtGui.QPushButton("Start", self)
layout.addWidget(self.progressBar)
layout.addWidget(button)
button.clicked.connect(self.onStart)
##############################################################
#and pass your argumetn to it's constructor here
self.myLongTask = TaskThread(myvar=myargument)
##############################################################
self.myLongTask.notifyProgress.connect(self.onProgress)
def onStart(self):
self.myLongTask.start()
def onProgress(self, i):
self.progressBar.setValue(i)
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