我有以下表格
餐桌农场
+---------+--------+-------------------+-----------+------------+
| FARM_ID |Stock_ID| FARM_TITLE | Size | FARM_VALUE |
+---------+--------+-------------------+-----------+------------+
| 2 | 1 | AgriZone | M | 202 |
| 3 | 1 | Cow Mill | L | 11 |
| 4 | 2 | Beef Farm | H | 540 |
| 5 | 2 | CattleOne | M | 1080 |
| 6 | 2 | FarmOne | L | 455 |
| 7 | 3 | Perdue | H | 333 |
| 8 | 4 | Holstein | M | 825 |
| 10 | 1 | Dotterers | H | 98 |
+---------+--------+-------------------+-----------+------------+
桌门
+---------+---------+------------+
| GATE_ID | FARM_ID | FARM_VALUE |
+---------+---------+------------+
| 1 | 2 | 0 |
| 1 | 3 | 0 |
| 1 | 4 | 540 |
| 2 | 4 | 550 |
| 3 | 4 | 560 |
| 4 | 4 | 570 |
| 5 | 4 | 580 |
| 6 | 4 | 590 |
| 1 | 5 | 1080 |
| 2 | 5 | 1100 |
| 3 | 5 | 1120 |
| 4 | 5 | 1140 |
| 5 | 5 | 1160 |
| 6 | 5 | 1180 |
| 1 | 6 | 455 |
| 2 | 6 | 536 |
| 3 | 6 | 617 |
| 4 | 6 | 698 |
| 5 | 6 | 779 |
| 6 | 6 | 860 |
| 1 | 7 | 0 |
| 1 | 8 | 0 |
| 1 | 10 | 0 |
+---------+---------+------------+
表原点
+--------+----------+
| ORI_ID | ORI_NAME |
+--------+----------+
| 1 | US |
| 2 | CA |
| 3 | MX |
+--------+----------+
表库存
+--------+--------+-------------------+
|Stock_ID| ORI_ID | Stock_TITLE |
+--------+--------+-------------------+
| 1 | 1 | P1 |
| 2 | 2 | P3 |
| 3 | 3 | Q4 |
| 4 | 3 | B3 |
+--------+--------+-------------------+
表结果
+-----------+---------+---------+------------+------------+
| RESULT_ID | FARM_ID | GATE_ID | FARM_VALUE | Score% |
+-----------+---------+---------+------------+------------+
| 1 | 7 | 1 | 333 | 100 |
| 2 | 8 | 1 | 825 | 100 |
| 3 | 6 | 1 | 455 | 40 |
| 4 | 6 | 2 | 536 | 0 |
| 5 | 6 | 3 | 617 | 0 |
| 6 | 6 | 4 | 698 | 100 |
| 7 | 6 | 5 | 779 | 0 |
| 8 | 6 | 6 | 860 | 10 |
| 9 | 4 | 1 | 540 | 100 |
| 10 | 4 | 2 | 550 | 90 |
| 11 | 4 | 3 | 560 | 0 |
| 12 | 4 | 4 | 570 | 100 |
| 13 | 4 | 5 | 580 | 10 |
| 14 | 4 | 6 | 590 | 0 |
| 15 | 5 | 1 | 1080 | 0 |
| 16 | 5 | 2 | 1100 | 0 |
| 17 | 5 | 3 | 1120 | 0 |
| 18 | 5 | 4 | 1140 | 50 |
| 19 | 5 | 5 | 1160 | 0 |
| 20 | 5 | 6 | 1180 | 100 |
| 21 | 3 | 1 | 11 | 100 |
| 22 | 10 | 1 | 98 | 90 |
| 23 | 2 | 1 | 202 | 100 |
+-----------+---------+---------+------------+------------+
带注释的结果表:同上^
+-----------+---------+---------+------------+------------+
| RESULT_ID | FARM_ID | GATE_ID | FARM_VALUE | Score% |
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 1 | 7 | 1 | 333 | 100 | <--|H-Case {H}
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 2 | 8 | 1 | 825 | 100 | <--|M-Case {M}
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 3 | 6 | 1 | 455 | 40 |
| 4 | 6 | 2 | 536 | 0 |
| 5 | 6 | 3 | 617 | 0 |
| 6 | 6 | 4 | 698 | 100 | <--|L
| 7 | 6 | 5 | 779 | 0 | |
| 8 | 6 | 6 | 860 | 10 | |
+-----------+---------+---------+------------+------------+ |
| 9 | 4 | 1 | 540 | 100 | |
| 10 | 4 | 2 | 550 | 90 | |
| 11 | 4 | 3 | 560 | 0 | |
| 12 | 4 | 4 | 570 | 100 | <--+M-case {H,M,L}
| 13 | 4 | 5 | 580 | 10 | |
| 14 | 4 | 6 | 590 | 0 | |
+-----------+---------+---------+------------+------------+ |
| 15 | 5 | 1 | 1080 | 0 | |
| 16 | 5 | 2 | 1100 | 0 | |
| 17 | 5 | 3 | 1120 | 0 | |
| 18 | 5 | 4 | 1140 | 50 | <--|H
| 19 | 5 | 5 | 1160 | 0 |
| 20 | 5 | 6 | 1180 | 100 |
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 21 | 3 | 1 | 11 | 100 | <--|L
| 22 | 10 | 1 | 98 | 90 | <--+H-case {H,M,L}
| 23 | 2 | 1 | 202 | 100 | <--|M
+-----------+---------+---------+------------+------------+
所需计算:
- Type 最多只能有三个值:{H,M,L};
- 当所有值都存在时,它们的分级如下:H=70 M=20 L=10
所有独特的案例都是
情况{H,M}:H=80 M=20
- 情况{M,L}:M=60 L=40
- 情况{H,L}:H=90 L=10
- 情况{H}:H=100
- 情况{M}:M=100
- 情况{L}:L=100
- 情况{H,M,L}:H=70 M=20 L=10
进一步说明
-
Only Stock with with atleast one
GATE
, fully satisfied can get 100 points max
- 例子:
Q4
有 3 套 6 个GATES
;只有一个GATE
必须满足设置(有分数)。
- 所给出的点必须乘以它所涉及的特定情况示例:
Q4
情况为 {H,M,L},这意味着 H=70; M=20; L=10 这将导致 (70*100%)+(20*50%)+(10*100%)=90(回顾上面的结果表注释)
2.
- 即使未完全满足某个门,仍应考虑并计算分数。当没有完全满足的门时,应保留获得 MAX 积分的门。 (如有不明白的会进一步解释)
如果我们执行查询来理解表和数据,它将如下所示
+---------+-----------+---------------+-----------+---------+-----------+---------+
| Origin | Stock | Farm Title | Farm Value| Gate | Size | Score |
+---------+-----------+---------------+-----------+---------+-----------+---------+
| US | P1 | Perdue | 333 | 1 | H | 100 |
| US | P3 | Holstein | 825 | 1 | M | 100 |
| CA | Q4 | FarmOne | 455 | 1 | L | 40 |
| CA | Q4 | FarmOne | 536 | 2 | L | 0 |
| CA | Q4 | FarmOne | 617 | 3 | L | 0 |
| CA | Q4 | FarmOne | 698 | 4 | L | 100 |
| CA | Q4 | FarmOne | 779 | 5 | L | 0 |
| CA | Q4 | FarmOne | 860 | 6 | L | 10 |
| CA | Q4 | Beef Farm | 540 | 1 | H | 0 |
| CA | Q4 | Beef Farm | 550 | 2 | H | 90 |
| CA | Q4 | Beef Farm | 560 | 3 | H | 0 |
| CA | Q4 | Beef Farm | 570 | 4 | H | 100 |
| CA | Q4 | Beef Farm | 580 | 5 | H | 10 |
| CA | Q4 | Beef Farm | 590 | 6 | H | 0 |
| CA | Q4 | CattleOne | 1080 | 1 | M | 0 |
| CA | Q4 | CattleOne | 1100 | 2 | M | 0 |
| CA | Q4 | CattleOne | 1120 | 3 | M | 0 |
| CA | Q4 | CattleOne | 1140 | 4 | M | 50 |
| CA | Q4 | CattleOne | 1160 | 5 | M | 100 |
| CA | Q4 | CattleOne | 1180 | 6 | M | 0 |
| MX | B3 | Cow Mill | 11 | 1 | L | 100 |
| MX | B3 | Dotterers | 98 | 1 | H | 90 |
| MX | B3 | AgriZone | 202 | 1 | M | 100 |
+---------+-----------+---------------+-----------+---------+-----------+---------+
渴望结果
+---------+-------------------+-------+
| Origin | Stock | score |
+---------+-------------------+-------+
| US | P1 | 100 |
| US | P3 | 100 |
| CA | Q4 | 90 |
| MX | B3 | 93 |
+---------+-------------------+-------+
Since origin
has a stock
其中由 3 个不同的farms
以及那些farms
have 6 gates
每个。只要有一个gate
-set(数字匹配gates
)被得分为某个值,我们可以考虑整个STOCK
完全找到了。这是唯一的方法stock
可以考虑100。
此外,并重申,STOCK
Q4 的情况为:{H,M,L} 以及所有gate (4)
在某种程度上被发现了。gate
4 的得分 (100% * H) + (50% * M) + (100% * L) 等于 (70*100%) + (20*50%) + (10*100%) = 90
因此:(取自上面)
| CA | Q4 | 90 |
QED
那么我需要什么帮助正在创建子查询/子选择来完成此计算。我在下面的 SQL 小提琴链接中设置了上述场景中的所有内容(以及我一直在处理的正在进行的查询)。
非常感谢 stackoverflow 社区。
> SqlFiddle中的上述问题可以在这里找到