我想绘制一个甜甜圈,我的脚本是
import numpy as np
import matplotlib.pyplot as plt
pi,sin,cos = np.pi,np.sin,np.cos
r1 = 1
r2 = 2
theta = np.linspace(0,2*pi,36)
x1 = r1*cos(theta)
y1 = r1*sin(theta)
x2 = r2*cos(theta)
y2 = r2*sin(theta)
如何获得红色填充区域的甜甜圈?
您可以遍历闭合曲线中的区域边界,并使用fill
填充该封闭区域内的区域的方法:
import numpy as np
import matplotlib.pyplot as plt
n, radii = 50, [.7, .95]
theta = np.linspace(0, 2*np.pi, n, endpoint=True)
xs = np.outer(radii, np.cos(theta))
ys = np.outer(radii, np.sin(theta))
# in order to have a closed area, the circles
# should be traversed in opposite directions
xs[1,:] = xs[1,::-1]
ys[1,:] = ys[1,::-1]
ax = plt.subplot(111, aspect='equal')
ax.fill(np.ravel(xs), np.ravel(ys), edgecolor='#348ABD')
plt.show()
这可以很容易地应用于任何形状,例如圆形内部或外部的五边形:
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