我有一个包含以下内容的 JSON:
{
"data": [
{
"name": "Test",
"program": {
"publicAccess": "--------",
"externalAccess": false,
"userGroupAccesses": [
{
"access": "r-------"
},
{
"access": "rw------"
}
],
"id": "MmBqeMLIC2r"
},
"publicAccess": "rw------"
}
]
}
我想删除所有匹配的键(递归地)publicAccess
or userGroupAccesses
,这样我的 JSON 看起来像这样:
{
"data": [
{
"name": "Test",
"program": {
"externalAccess": false,
"id": "MmBqeMLIC2r"
}
}
]
}
我已经复制了jq
的内置walk
函数来自source.
# Apply f to composite entities recursively, and to atoms
def walk(f):
. as $in
| if type == "object" then
reduce keys[] as $key
( {}; . + { ($key): ($in[$key] | walk(f)) } ) | f
elif type == "array" then map( walk(f) ) | f
else f
end;
# My Code
walk(if (type == "object" and .publicAccess)
then del(.publicAccess)
elif (type == "array" and .userGroupAccesses)
then del(.userGroupAccesses)
else
.
end )
给我jq: error (at <stdin>:2622): Cannot index array with string "userGroupAccesses"
。另外如果我使用.userGroupAccesses[]
- 我如何得到结果?
jqplay 上的片段:https://jqplay.org/s/1m7wAeHMTu