我尝试在 Windows 上使用 os.scandir() 而不是 os.listdir() 来优化用 Python 编写的文件浏览功能。然而时间没有变化,大概是2分半钟左右,我也说不上来为什么。
以下是原始和更改后的功能:
os.listdir() 版本:
def browse(self, path, tree):
# for each entry in the path
for entry in os.listdir(path):
entity_path = os.path.join(path, entry)
# check if support by git or not
if self.git_ignore(entity_path) is False:
# if is a dir create a new level in the tree
if os.path.isdir( entity_path ):
tree[entry] = Folder(entry)
self.browse(entity_path, tree[entry])
# if is a file add it to the tree
if os.path.isfile(entity_path):
tree[entry] = File(entity_path)
os.scandir() 版本:
def browse(self, path, tree):
# for each entry in the path
for dirEntry in os.scandir(path):
entry_path = dirEntry.name
entity_path = dirEntry.path
# check if support by git or not
if self.git_ignore(entity_path) is False:
# if is a dir create a new level in the tree
if dirEntry.is_dir(follow_symlinks=True):
tree[entry_path] = Folder(entity_path)
self.browse(entity_path, tree[entry_path])
# if is a file add it to the tree
if dirEntry.is_file(follow_symlinks=True):
tree[entry_path] = File(entity_path)
此外,以下是该函数中使用的辅助函数:
def git_ignore(self, filepath):
if '.git' in filepath:
return True
if '.ci' in filepath:
return True
if '.delivery' in filepath:
return True
child = subprocess.Popen(['git', 'check-ignore', str(filepath)],
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
output = child.communicate()[0]
status = child.wait()
return status == 0
============================================================
class Folder(dict):
def __init__(self, path):
self.path = path
self.categories = {}
============================================================
class File(object):
def __init__(self, path):
self.path = path
self.filename, self.extension = os.path.splitext(self.path)
有人有办法让我的函数运行得更快吗?我的假设是,在开始时提取名称和路径会使其运行速度比应有的速度慢,这是正确的吗?