如何在node.js中的“require”之后删除模块？

比方说，在我需要一个模块并执行以下操作之后：

var b = require('./b.js');
--- do something with b ---

然后我想拿走模块b（即清理缓存）。我怎样才能做到呢？

原因是我想动态加载/删除或更新模块而不重新启动节点服务器。任何想法？

- - - - 更多的 - - - - 根据删除require.cache的建议，它仍然不起作用......

what I did are few things:
1) delete require.cache[require.resolve('./b.js')];
2) loop for every require.cache's children and remove any child who is b.js
3) delete b

然而，当我打电话给b时，它仍然在那里！它仍然可以访问。除非我这样做：

b = {};

不确定这是否是处理这个问题的好方法。 因为如果稍后，我在 b.js 被修改时再次需要 ('./b.js') 。它需要旧的缓存 b.js （我试图删除它）还是新的？

----------- 更多发现 --------------

好的。我做了更多测试并使用代码..这是我发现的：

1) delete require.cache[]  is essential.  Only if it is deleted, 
 then the next time I load a new b.js will take effect.
2) looping through require.cache[] and delete any entry in the 
 children with the full filename of b.js doesn't take any effect.  i.e.
u can delete or leave it.  However, I'm unsure if there is any side
effect.  I think it is a good idea to keep it clean and delete it if
there is no performance impact.
3) of course, assign b={} doesn't really necessary, but i think it is 
 useful to also keep it clean.

您可以使用它来删除缓存中的条目：

delete require.cache[require.resolve('./b.js')]

require.resolve()将找出完整路径./b.js，用作缓存键。