所以我想做一些像下面这样的sql代码：
select s.id, s.name,s.city
from stuff s
group by s.name having count(where city and name are identical) > 1
要生成以下内容（但忽略仅名称或仅城市匹配的位置，它必须位于两列上）：
id name city
904834 jim London
904835 jim London
90145 Fred Paris
90132 Fred Paris
90133 Fred Paris
重复的id成对的name and city:
select s.id, t.*
from [stuff] s
join (
select name, city, count(*) as qty
from [stuff]
group by name, city
having count(*) > 1
) t on s.name = t.name and s.city = t.city
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