C# 正则表达式排除字符串

我得到了一个字符串集合，我想要的正则表达式就是收集所有以 http 开头的..

href="http://www.test.com/cat/1-one_piece_episodes/"href="http://www.test.com/cat/2-movies_english_subbed/"href="http://www.test .com/cat/3-english_dubbed/"href="http://www.exclude.com"

这是我的正则表达式模式..

href="(.*?)[^#]"

并返回这个

href="http://www.test.com/cat/1-one_piece_episodes/"
href="http://www.test.com/cat/2-movies_english_subbed/"
href="http://www.xxxx.com/cat/3-english_dubbed/"
href="http://www.exclude.com"

排除最后一个匹配的模式是什么..或排除具有以下内容的匹配exclude内部域名，例如 href="http://www.exclude.com"

EDIT:对于多重排除

href="((?:(?!"|\bexclude\b|\bxxxx\b).)*)[^#]"

@ridgerunner 和我会将正则表达式更改为：

href="((?:(?!\bexclude\b)[^"])*)[^#]"

它匹配所有href属性，只要它们不以#并且不包含这个词exclude.

解释：

href="     # Match href="
(          # Capture...
 (?:       # the following group:
  (?!      # Look ahead to check that the next part of the string isn't...
   \b      # the entire word
   exclude # exclude
   \b      # (\b are word boundary anchors)
  )        # End of lookahead
  [^"]     # If successful, match any character except for a quote
 )*        # Repeat as often as possible
)          # End of capturing group 1
[^#]"      # Match a non-# character and the closing quote.

允许多个“禁止词”：

href="((?:(?!\b(?:exclude|this|too)\b)[^"])*)[^#]"