考虑到$vars
是你想要得到的变量one['one-one']
or two['two-two']['more']
from (Demo):
$vars = function($str) use ($vars)
{
$c = function($v, $w) {return $w ? $v[$w] : $v;};
return array_reduce(preg_split('~\[\'|\'\]~', $str), $c, $vars);
};
echo $vars("one['one-one']"); # hello
echo $vars("two['two-two']['more']"); # tea-time!
这是将字符串词法分析为key令牌,然后遍历$vars
数组上的keyed值,而$vars
数组已变成函数。
旧的东西:
使用仅 eval 的函数重载数组:
$vars = array(
'one' => array(
'one-one' => "hello",
'one-two' => "goodbye"
),
'two' => array(
'two-one' => "foo",
'two-two' => "bar"
)
);
$vars = function($str) use ($vars)
{
return eval('return $vars'.$str.';');
};
echo $vars("['one']['one-two']"); # goodbye
如果您不喜欢 eval,请更改实现:
$vars = function($str) use ($vars)
{
$r = preg_match_all('~\[\'([a-z-]+)\']~', $str, $keys);
$var = $vars;
foreach($keys[1] as $key)
$var = $var[$key];
return $var;
};
echo $vars("['one']['one-two']"); # goodbye