我正在学习 ASP.NET MVC 3 并尝试创建一个具有单个表单的视图,该表单由通过外键链接在一起的多个模型组成。最终目标是将单个表单插入到所有数据库表中。
问题是,我无法弄清楚为什么当我右键单击创建视图时,表单没有在 cshtml 文件中自动生成。自动生成的代码很有帮助,因为我有许多链接在一起的表,以及必须验证和插入的许多字段。如果无法自动生成表单,那么最有效/最优雅的方法是什么?
这是我所拥有的内容的简化。
Model:
class Customer
{
[Key]
public UInt64 CustomerId { get; set; }
[Required(ErrorMessage = "Name is required.")]
[Display(Name = "Customer Name")]
[MaxLength(50)]
public string FullName { get; set; }
}
class CustomerAdditionalDetails1
{
[ForeignKey("Customer")]
public UInt64 CustomerId { get; set; }
[Required(ErrorMessage = "This info is required.")]
[Display(Name = "Customer Information")]
[MaxLength(50)]
public string SomeInfo { get; set; }
}
class CustomerAdditionalDetails2
{ // same foreign key as CustomerAddtionalDetails1, but with different properties
}
class CustomerAdditionalDetails3
{ // same foreign key as CustomerAddtionalDetails1, but with different properties
}
...
public class CustomerModel
{
public Customer Customer { get; set; }
public CustomerAdditionalDetails1 CustomerAdditionalDetails1 { get; set; }
public CustomerAdditionalDetails2 CustomerAdditionalDetails2 { get; set; }
public CustomerAdditionalDetails3 CustomerAdditionalDetails3 { get; set; }
...
}
控制器:
public ActionResult Submit()
{
return View();
}
[HttpPost]
public ActionResult Submit(CustomerModel customer)
{
return View();
}
请帮忙!
当您生成视图时,您是否基于 CustomerModel 创建强类型视图?如果您生成视图,则不会在页面中输出任何值,因为您的所有属性都是对其他对象的引用。您需要模型中包含实际值类型,以便脚手架将它们自动包含在视图中。也就是说,您始终可以按照下面的示例自行将它们添加到视图中。
我还注意到在您的控制器中,您的 GET 方法不会将模型返回到要渲染的视图。如果您想基于模型生成视图,那么您需要传递您希望为其生成视图的对象。
@model MvcApplication3.Models.CustomerModel
@{
ViewBag.Title = "Index";
}
<h2>Index</h2>
<fieldset>
<legend>CustomerModel</legend>
</fieldset>
<ul>
<li>@Model.Customer.FullName</li>
<li>@Model.CustomerAdditionalDetails1.SomeInfo1</li>
<li>@Model.CustomerAdditionalDetails2.SomeInfo2</li>
</ul>
<p>
@Html.ActionLink("Edit", "Edit", new { /* id=Model.PrimaryKey */ }) |
@Html.ActionLink("Back to List", "Index")
</p>
public class CustomerController : Controller
{
public ActionResult Index()
{
CustomerModel customerModel = new CustomerModel()
{
Customer = new Customer()
{
FullName = "Dan"
},
CustomerAdditionalDetails1 = new CustomerAdditionalDetails1()
{
SomeInfo1 = "Somewhere1"
},
CustomerAdditionalDetails2 = new CustomerAdditionalDetails2()
{
SomeInfo2 = "Somewhere2"
},
CustomerAdditionalDetails3 = new CustomerAdditionalDetails3()
{
SomeInfo3 = "Somewhere3"
}
};
return View(customerModel);
}
}
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