在 R 中每小时对数据帧进行分组

我有一个数据框，其中日期列中有日期时间值，三列包含每个日期时间的计数。

我正在尝试将每小时的数据与三列的计数进行分组

聚合函数适用于单列，但我试图对整个数据框执行此操作。有小费吗？

aggregate(DateFreq$ColA,by=list((substr(DateFreq$Date,1,13))),sum) 

您可以使用dplyr使用进行聚合dplyr::group_by and dplyr::summarise:

library(lubridate)
library(anytime)
library(tidyverse)

Lines <- "Date,c1,c2,c3
06/25/2013 12:01,0,1,1
06/25/2013 12:08,-1,1,1
06/25/2013 12:48,0,1,1
06/25/2013 12:58,0,1,1
06/25/2013 13:01,0,1,1
06/25/2013 13:08,0,1,1
06/25/2013 13:48,0,1,1
06/25/2013 13:58,0,1,1
06/25/2013 14:01,0,1,1
06/25/2013 14:08,0,1,1
06/25/2013 14:48,0,1,1
06/25/2013 14:58,0,1,1"

setClass("myDate")
setAs("character","myDate", function(from) anytime(from))
df <- read.csv(text = Lines, header=TRUE,  colClasses = c("myDate", "numeric", "numeric", "numeric"))

df %>%
  group_by(Date=floor_date(Date, "1 hour")) %>%
  summarize(c1=sum(c1), c2=sum(c2), c3=sum(c3))
# A tibble: 3 × 4
                 Date    c1    c2    c3
               <dttm> <dbl> <dbl> <dbl>
1 2013-06-25 12:00:00    -1     4     4
2 2013-06-25 13:00:00     0     4     4
3 2013-06-25 14:00:00     0     4     4