给定一个数组,将数组的元素反向输出
方法一:直接反向遍历输出
public static void main(String[] args) {
int[] a={52,14,65,98,15,35};
System.out.println(Arrays.toString(a));
fz(a);
}
public static void fz(int[] a){
for (int i = a.length; i >=0; i--) {
System.out.println(a[i]);
}
}
方法二:用一个新的数组接收
public static void main(String[] args) {
int[] a={52,14,65,98,15,35};
System.out.println("翻转前"+Arrays.toString(a));
System.out.println("翻转后"+Arrays.toString(fz(a)));
}
public static int[] fz(int[] a){
int[] b=new int[a.length];
for (int i = 0; i < a.length; i++) {
b[i]=a[a.length-1-i];
}
return b;
}
方法三:将数组的元素互换
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入数组长度");
int a = scanner.nextInt();
int[] b = new int[a];
System.out.println("请输入数值元素");
for (int i = 0; i < a; i++) {
b[i] = scanner.nextInt();
}
System.out.println("翻转前"+Arrays.toString(b));
fx(b);
System.out.println("翻转后"+Arrays.toString(b));
}
static void fx(int[] a){
for (int i = 0; i < a.length/2; i++) {
int temp=a[i];
a[i]=a[a.length-1-i];
a[a.length-1-i]=temp;
}
}
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