不同模块中的类名相同

我需要在 swift 5 中使用两个同名的类。为此，我在两个不同的模块中创建了这两个类，但我对如何在UIViewController

我的一堂课是Person这是在models > student模块和另一个类是Person与 是在models module

我尝试过导入类

import class models.student.Person

class BookViewController: UIViewController {
     var students:[Person] = [] //it should call models.student.Person
     var people: [Person] = [] //it should call models.Person
     ...

但上面的 Person 类指向models.Person只是，它并不指向models.student.Person

模型中的 Person 类 > Person.swift 是

import Foundation

// MARK: - Person
public struct Person: Codable {
    public let firstName: String?
    public let lastName: String?
    public let address: String?
    public let phone: String?

    enum CodingKeys: String, CodingKey {
        case firstName = "first_name"
        case lastName = "last_name"
        case address = "address"
        case phone = "phone"
    }

    public init(firstName: String?, lastName: String?, address: String?, phone: String?) {
        self.firstName = firstName
        self.lastName = lastName
        self.address = address
        self.phone = phone
    }
}

和 models.student.Person.swift 是

import Foundation

// MARK: - Person
public struct Person: Codable {
    public let fullName: String?
    public let educationalQualification: String?
    public let college: String?

    enum CodingKeys: String, CodingKey {
        case fullName = "full_name"
        case educationalQualification = "educational_qualification"
        case college = "college"
    }

    public init(fullName: String?, educationalQualification: String?, college: String?) {
        self.fullName = fullName
        self.educationalQualification = educationalQualification
        self.college = college
    }
}

我需要我的课程BookViewController

我无法将类名更改为不同的类名，我应该使用相同的类名。

您可以尝试类型别名：

typealias StudentPerson = yourStudentFramework.Person

然后像这样使用它：

import yourStudentFramework

class BookViewController: UIViewController {
     var students:[StudentPerson] = [] //it should call yourStudentFramework.Person
     var people: [Person] = [] //it should call models.Person
...