更新下面的代码
我发现一些代码能够上传图像并显示其缩略图。但是，我也想将图像保存到特定文件夹中。
我可以使用什么 jQuery 代码或 ajax 代码将原始图像保存到我选择的文件夹中？
这是现场演示：http://jsfiddle.net/dn9Sr/2/
这是完整的代码：
<html>
<head>
<script src="http://code.jquery.com/jquery-1.8.3.js" type="text/javascript"></script>
<style>
.input-file-row-1:after {
content: ".";
display: block;
clear: both;
visibility: hidden;
line-height: 0;
height: 0;
}
.input-file-row-1{
display: inline-block;
margin-top: 25px;
position: relative;
}
#preview_image {
display: none;
width: 90px;
height: 90px;
margin: 2px 0px 0px 5px;
border-radius: 10px;
}
.upload-file-container {
position: relative;
width: 100px;
height: 137px;
overflow: hidden;
background: url(http://i.imgur.com/AeUEdJb.png) top center no-repeat;
float: left;
margin-left: 23px;
}
.upload-file-container-text{
font-family: Arial, sans-serif;
font-size: 12px;
color: #719d2b;
line-height: 17px;
text-align: center;
display: block;
position: absolute;
left: 0;
bottom: 0;
width: 100px;
height: 35px;
}
.upload-file-container-text > span{
border-bottom: 1px solid #719d2b;
cursor: pointer;
}
.one_opacity_0 {
opacity: 0;
height: 0;
width: 1px;
float: left;
}
</style>
<script>
$( document ).ready(function() {
function readURL(input, target) {
if (input.files && input.files[0]) {
var reader = new FileReader();
var image_target = $(target);
reader.onload = function (e) {
image_target.attr('src', e.target.result).show();
};
reader.readAsDataURL(input.files[0]);
}
}
$("#patient_pic").live("change",function(){
readURL(this, "#preview_image")
});
});
</script>
</head>
<body>
<form name="" method="post" action="#" class="feedback-form-1">
<fieldset>
<div class="input-file-row-1">
<div class="upload-file-container">
<img id="preview_image" src="#" alt="" />
<div class="upload-file-container-text">
<div class = 'one_opacity_0'>
<input type="file" id="patient_pic" label = "add" />
</div>
<span> Add Photo </span>
</div>
</div>
</div>
</fieldset>
</form>
</body>
</html>
更新：我认为我走在正确的轨道上。我很接近，但我不知道要从 jQuery 发送什么数据。我添加了一个 php scrit 并成功回调，但我没有发送正确的变量。我想如果我发送正确的值我就能得到它。
代码：
<script>
$( document ).ready(function() {
function readURL(input, target) {
if (input.files && input.files[0]) {
var reader = new FileReader();
var image_target = $(target);
reader.onload = function (e) {
image_target.attr('src', e.target.result).show();
$.ajax({
type:'POST',
url: 'theUpload.php',
data: input.files[0],
success:function(data){
console.log("success");
console.log(data);
alert(data);
},
error: function(data){
console.log("error");
console.log(data);
}
});
};
reader.readAsDataURL(input.files[0]);
}
}
$("#patient_pic").live("change",function(){
readURL(this, "#preview_image")
});
});
</script>
