传递父类作为参数？

是否可以在创建实例之前不指定父类？
例如像这样的东西：

class SomeParentClass:
    # something

class Child(unspecifiedParentClass):
    # something

instance = Child(SomeParentClass)

这显然是行不通的。但有可能以某种方式做到这一点吗？

您可以更改类中实例的类'__init__() method:

class Child(object):
    def __init__(self, baseclass):
        self.__class__ = type(self.__class__.__name__,
                              (baseclass, object),
                              dict(self.__class__.__dict__))
        super(self.__class__, self).__init__()
        print 'initializing Child instance'
        # continue with Child class' initialization...

class SomeParentClass(object):
    def __init__(self):
        print 'initializing SomeParentClass instance'
    def hello(self):
        print 'in SomeParentClass.hello()'

c = Child(SomeParentClass)
c.hello()

Output:

initializing SomeParentClass instance
initializing Child instance
in SomeParentClass.hello()