我正在尝试从 python 脚本向 Mountain Lion 发送通知，并对通知的点击做出反应。发送通知现在可以完美地找到。但我无法让 Lion 在单击时回调我的脚本。
这就是我所做的。我实现了一个通知类。该类实例的唯一目的是通过调用来提供通知notify()。在同一方法中，我设置了应用程序委托的对象。
import Foundation
import objc
import AppKit
class MountainLionNotification(Foundation.NSObject, Notification):
def notify(self, title, subtitle, text, url):
NSUserNotification = objc.lookUpClass('NSUserNotification')
NSUserNotificationCenter = objc.lookUpClass('NSUserNotificationCenter')
notification = NSUserNotification.alloc().init()
notification.setTitle_(str(title))
notification.setSubtitle_(str(subtitle))
notification.setInformativeText_(str(text))
notification.setSoundName_("NSUserNotificationDefaultSoundName")
notification.setUserInfo_({"action":"open_url", "value":url})
AppKit.NSApplication.sharedApplication().setDelegate_(self)
NSUserNotificationCenter.defaultUserNotificationCenter().scheduleNotification_(notification)
def applicationDidFinishLaunching_(self, sender):
userInfo = sender.userInfo()
if userInfo["action"] == "open_url":
import subprocess
subprocess.Popen(['open', userInfo["value"]])
现在我期望applicationDidFinishLaunching_()单击通知时调用。不幸的是，这种情况永远不会发生。我究竟做错了什么？
好的，找到了。没有跑AppHelper.runEventLoop()。明显是打脸失误。以下代码有效：
class MountainLionNotification(Foundation.NSObject, Notification):
def notify(self, title, subtitle, text, url):
NSUserNotification = objc.lookUpClass('NSUserNotification')
NSUserNotificationCenter = objc.lookUpClass('NSUserNotificationCenter')
notification = NSUserNotification.alloc().init()
notification.setTitle_(str(title))
notification.setSubtitle_(str(subtitle))
notification.setInformativeText_(str(text))
notification.setSoundName_("NSUserNotificationDefaultSoundName")
notification.setHasActionButton_(True)
notification.setOtherButtonTitle_("View")
notification.setUserInfo_({"action":"open_url", "value":url})
NSUserNotificationCenter.defaultUserNotificationCenter().setDelegate_(self)
NSUserNotificationCenter.defaultUserNotificationCenter().scheduleNotification_(notification)
def userNotificationCenter_didActivateNotification_(self, center, notification):
userInfo = notification.userInfo()
if userInfo["action"] == "open_url":
import subprocess
subprocess.Popen(['open', userInfo["value"]])
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