QTableWidgetItem *QTableWidget::item(int row, int column)
const
如果已设置,则返回给定行和列的项目;否则返回 0。
Try it:
import sys
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
from PyQt5.QtCore import *
class Example(QMainWindow):
def __init__(self, data):
super().__init__()
self.data = data
self.cols = len(self.data[0])
self.row, self.col = 0, 0
self.cell = []
centralWidget = QWidget()
self.setCentralWidget(centralWidget)
self.label = QLabel(alignment=Qt.AlignCenter)
self.tableWidget = QTableWidget(0, 4)
self.tableWidget.setHorizontalHeaderLabels(["Id", "Test name", "Owner", "Script source"])
self.tableWidget.cellClicked.connect(self.cellClick)
self.setTableWidget()
self.btnRun = QPushButton("btnRun")
self.btnRun.clicked.connect(self.run_selected_test)
lay = QGridLayout(centralWidget)
lay.addWidget(self.label, 0, 0)
lay.addWidget(self.tableWidget, 1, 0)
lay.addWidget(self.btnRun, 2, 0)
def run_selected_test(self):
self.cell = []
for col in range(self.cols):
self.cell.append(self.tableWidget.item(self.row, col).text()) # <---
self.label.setText("{}".format(" {} ; "*self.cols).format(*self.cell))
def cellClick(self, row, col):
self.row = row
self.col = col
def setTableWidget(self):
for r, (_id, _name, _owner, _script) in enumerate(self.data):
it_id = QTableWidgetItem(_id)
it_name = QTableWidgetItem(_name)
it_owner = QTableWidgetItem(_owner)
it_script = QTableWidgetItem(_script)
self.tableWidget.insertRow(self.tableWidget.rowCount())
for c, item in enumerate((it_id, it_name, it_owner, it_script)):
self.tableWidget.setItem(r, c, item)
data = [("1", "Login", "1", "test_login_s"),
("2", "Logout", "1", "test_logout_s"),
("3", "User > Edit", "1", "test_user_edit_s")]
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example(data)
ex.setGeometry(300, 150, 450, 200)
ex.show()
sys.exit(app.exec_())