将强类型属性名称作为参数传递

我有一个收藏IEnumerable<School>正在传递给扩展 填充的方法DropDownList。我也想通过DataValueField and DataTextField作为一个论据，但我希望它们是 强类型。

基本上，我不想通过string为了DataValueField and DataTextField争论，很容易出错。

public static void populateDropDownList<T>(this DropDownList source,
        IEnumerable<T> dataSource,
        Func<T, string> dataValueField,
        Func<T, string> dataTextField) {
    source.DataValueField = dataValueField; //<-- this is wrong
    source.DataTextField = dataTextField; //<-- this is wrong
    source.DataSource = dataSource;
    source.DataBind();
}

就这样称呼...

myDropDownList.populateDropDownList(states,
        school => school.stateCode,
        school => school.stateName);

我的问题是，我怎样才能通过DataValueField and DataTextField强类型作为填充下拉列表的参数？

根据乔恩的回答和this帖子，它给了我一个想法。我通过了DataValueField and DataTextField as Expression<Func<TObject, TProperty>>到我的扩展方法。我创建了一个接受该表达式并返回的方法MemberInfo对于该财产。那么我所要做的就是打电话.Name我有我的string.

哦，我将扩展方法名称更改为populate，很丑。

public static void populate<TObject, TProperty>(
        this DropDownList source, 
        IEnumerable<TObject> dataSource, 
        Expression<Func<TObject, TProperty>> dataValueField, 
        Expression<Func<TObject, TProperty>> dataTextField) {
    source.DataValueField = getMemberInfo(dataValueField).Name;
    source.DataTextField = getMemberInfo(dataTextField).Name;
    source.DataSource = dataSource;
    source.DataBind();
}

private static MemberInfo getMemberInfo<TObject, TProperty>(Expression<Func<TObject, TProperty>> expression) {
    var member = expression.Body as MemberExpression;
    if(member != null) {
        return member.Member;
    }
    throw new ArgumentException("Member does not exist.");
}

就这样称呼...

myDropDownList.populate(states,
    school => school.stateCode,
    school => school.stateName);