我在使用一个在屏幕上显示图像两秒钟然后被破坏的函数时遇到问题。当程序运行时,函数初始调用程序正常工作,但如果随后通过 tkinter 中内置的按钮调用该函数,则会出现错误。
appcwd = os.getcwd()
user32 = ctypes.windll.user32
screensize = user32.GetSystemMetrics(0), user32.GetSystemMetrics(1)
size = str(screensize[0])+'x'+str(screensize[1])
def wlcm_scrn(event=None):
def destroy_wlcm(event=None):
wlcm_scrn.destroy()
global appcwd
global screensize
wlcm_scrn = tkinter.Tk()
file=appcwd+"\\Run_Files\\splash.gif"
splsh_img = tkinter.PhotoImage(file=file)
splosh = tkinter.Label(wlcm_scrn,image=splsh_img)
wlcmh = splsh_img.height()/2
wlcmw = splsh_img.width()/2
splosh.pack()
wlcm_scrn.config(bg='black')
wlcm_scrn.overrideredirect(True)
wlcm_scrn.bind("<Escape>",destroy_wlcm)
wlxym = '+'+str(int((screensize[0]/2)-wlcmw))+'+'+str(int((screensize[1]/2)-wlcmh))
wlcm_scrn.geometry(wlxym)
wlcm_scrn.wm_attributes("-topmost", 1)
wlcm_scrn.after(2000,destroy_wlcm)
wlcm_scrn.mainloop()
wlcm_scrn() #Call through procedure.
调用该函数的按钮。
view_img = tkinter.Button(cfrm,text='Show splash image',command=wlcm_scrn)
通过按钮命令调用时出现错误消息。
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Python33\lib\tkinter\__init__.py", line 1475, in __call__
return self.func(*args)
File "C:\Python33\POS_Solution\Rattle_Hum_POS.py", line 1755, in run_wlcm_scrn
wlcm_scrn()
File "C:\Python33\POS_Solution\Rattle_Hum_POS.py", line 34, in wlcm_scrn
splosh = tkinter.Label(wlcm_scrn,image=splsh_img)
File "C:\Python33\lib\tkinter\__init__.py", line 2596, in __init__
Widget.__init__(self, master, 'label', cnf, kw)
File "C:\Python33\lib\tkinter\__init__.py", line 2075, in __init__
(widgetName, self._w) + extra + self._options(cnf))
_tkinter.TclError: image "pyimage3" doesn't exist
什么是“pyimage3”以及为什么它不存在?
任何帮助,将不胜感激。谢谢。