Django 简单标签在 if 条件下不起作用

我想通过使用审核工具添加块来自定义 django-admin 的视频对象更改表单。

当我在 if 条件下使用自定义 simpletags 时 - 它不起作用。

模型.py：

class Video(models.Model):

    class Meta:
        db_table = 'video'

    DRAFT = 1
    MODERATION = 2
    PUBLISHED = 3
    REJECTED = 4
    HOSTING_UPLOADING = 5
    SUSPICIOUS = 6

    PUBLICATION_STATUSES = (
        (DRAFT, 'draft'),
        (MODERATION, 'moderation'),
        (PUBLISHED, 'published'),
        (HOSTING_UPLOADING, 'hosting uploading'),
        (REJECTED, 'rejected'),
        (SUSPICIOUS, 'suspicious')
    )

    video_pk = models.AutoField(primary_key=True)
    name = models.CharField(max_length=150, blank=True)
    hosting_id = models.CharField(max_length=20, blank=True)
    publication_status = models.PositiveSmallIntegerField(choices=PUBLICATION_STATUSES, default=MODERATION)

templatetags video_publication_statuses.py：

from api.models import Video
from django import template

register = template.Library()

@register.simple_tag
def moderation(status):
    return status == Video.MODERATION


@register.simple_tag
def suspicious(status):
    return status == Video.SUSPICIOUS


@register.simple_tag
def published(status):
    return status == Video.PUBLISHED


@register.simple_tag
def hosting_uploading(status):
    return status == Video.HOSTING_UPLOADING


@register.simple_tag
def rejected(status):
    return status == Video.REJECTED

更改表单.html：

{% extends "admin/change_form.html" %}
{% load video_publication_statuses %}
{% suspicious original.publication_status as suspicious_status %}
{% moderation original.publication_status as moderation_status %}
{% hosting_uploading original.publication_status as hosting_uploading_status %}
{% published original.publication_status as published_status %}
{% rejected original.publication_status as rejected_status %}

{% block after_related_objects %}
  {% if original.pk %}
    {% for fieldset in adminform %}
      {% if fieldset.name == 'Moderation' %}
        {% include "admin/includes/fieldset.html" %}
      {% endif %}
    {% endfor %}
    <div class="submit-row">
      {% if rejected_status or moderation_status or suspicious_status %}
        <input type="submit" value="Publish" name="publish" >
      {% endif %}
      {% if published_status %}
        <input type="submit" value="Reject" name="reject" >
      {% endif %}
    </div>
  {% endif %}
{% endblock %}

当我使用显式值而不是标签时，它可以工作：

  {% if original.publication_status == 3 %}
    <input type="submit" value="Reject" name="reject" >
  {% endif %}

请帮助我理解标签有什么问题？

我相信发生这种情况是因为模板标签传递字符串，并且您正在根据整数检查字符串，例如return "3" == 3

但从广义上讲，您将大量逻辑放入模板中，我通常会避免这种情况。模板标签保留用于“表示逻辑”，我认为这意味着“改变某些内容的呈现方式”，而不是改变所查看的内容。该逻辑属于视图或模型本身。

将此逻辑放入您的模型中应该很容易。

class Original(...):
  def rejected(self):
    return self.status == Video.rejected