使用 KSOAP Android 创建 SOAP 请求

我需要生成一个像这样的肥皂请求。

SOAP请求

POST /TennisMasters/TennisMasters.Listener.asmx HTTP/1.1
Host: playinkstudio.com
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://playinktennismasters.com/authenticateUser"

    <?xml version="1.0" encoding="utf-8"?>
    <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
      <soap:Body>
        <authenticateUser xmlns="http://playinktennismasters.com/">
          <user>string</user>
        </authenticateUser>
      </soap:Body>
    </soap:Envelope>

我正在使用 KSOAP2 来构建此请求。

private static String SOAP_ACTION = "http://playinktennismasters.com/authenticateUser";
private static String NAMESPACE = "http://playinktennismasters.com/";
private static String METHOD_NAME = "authenticateUser";
private static String URL = "http://playinkstudio.com/TennisMasters/TennisMasters.Listener.asmx";

    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    request.addProperty("user", "A Json String will be here");

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
            SoapEnvelope.VER12);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.debug = true;
    try {
        androidHttpTransport.call(SOAP_ACTION, envelope);
    } catch (Exception e) {
        e.printStackTrace();
    }

这是我调试时得到的请求。

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://www.w3.org/2003/05/soap-encoding" xmlns:v="http://www.w3.org/2003/05/soap-envelope">
<v:Header />
<v:Body>
<authenticateUser xmlns="http://playinktennismasters.com/" **id="o0" c:root="1"**>
<user **i:type="d:string"**>{"email":"[email protected]","UserDate":"Feb 22, 2012 7:01:24 PM","GearId":0,"GearValue":0,"Income":0,"Level":0,"MatchResult":0,"MatchType":0,"OfferId":0,"OpponentId":0,"Partners":0,"ExhibitionCount":0,"PowerRuns":0,"PowerServes":0,"PowerShots":0,"Seeds":0,"Energy":0,"Cash":0,"Stamina":0,"Strength":0,"SubLevel":0,"TotalEnergy":0,"TotalStamina":0,"TrainingId":0,"Agility":0,"UserId":0,"Age":0,"ActivityId":0,"gearIsGift":0}</user>
</authenticateUser>
</v:Body>
</v:Envelope>

我不知道为什么在authenticateUser.xml中添加了“id”和“c：root”等额外属性。 以及 i:type="d:String" 中的额外属性。 请有人给我一个很好的例子或教程，它可以指导我创建像上面这样的请求，真的需要帮助，谢谢。

我使用了简单的 HttpClient 和 Httppost， 请求信封的简单字符串。

        String temp = "<?xml version=\"1.0\" encoding=\"utf-8\"?>"
            + "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">"
            + "<soap:Body>"
            + "<authenticateUser xmlns=\"http://playinktennismasters.com/\">"
            + "<user>%s</user>" + "</authenticateUser>" + "</soap:Body>"
            + "</soap:Envelope>";
    ENVELOPE = String.format(temp, user);

现在使用方法将创建发布请求剩余参数并返回响应字符串。

public String CallWebService(String url, String soapAction, String envelope) {
    final DefaultHttpClient httpClient = new DefaultHttpClient();
    // request parameters
    HttpParams params = httpClient.getParams();
    HttpConnectionParams.setConnectionTimeout(params, 10000);
    HttpConnectionParams.setSoTimeout(params, 15000);
    // set parameter
    HttpProtocolParams.setUseExpectContinue(httpClient.getParams(), true);

    // POST the envelope
    HttpPost httppost = new HttpPost(url);
    // add headers
    httppost.setHeader("soapaction", soapAction);
    httppost.setHeader("Content-Type", "text/xml; charset=utf-8");

    String responseString = "Nothingggg";
    try {

        // the entity holds the request
        HttpEntity entity = new StringEntity(envelope);
        httppost.setEntity(entity);

        // Response handler
        ResponseHandler<String> rh = new ResponseHandler<String>() {
            // invoked when client receives response
            public String handleResponse(HttpResponse response)
                    throws ClientProtocolException, IOException {

                // get response entity
                HttpEntity entity = response.getEntity();

                // read the response as byte array
                StringBuffer out = new StringBuffer();
                byte[] b = EntityUtils.toByteArray(entity);

                // write the response byte array to a string buffer
                out.append(new String(b, 0, b.length));
                return out.toString();
            }
        };

         responseString = httpClient.execute(httppost, rh);

    } catch (Exception e) {
        e.printStackTrace();
        Log.d("me","Exc : "+ e.toString());

    }

    // close the connection
    httpClient.getConnectionManager().shutdown();
    return responseString;
}