我不明白为什么它总是返回 arg1 的值。我正在建造一个重量转换器。
public double convert(double arg1,int arg2,int arg3) {
// arg1 = amount, arg2 = from, arg3 = to
double milligram = 1;
double gram = 1000;
double ounce = 28349.5;
double pound = 453592;
double answer = 0;
switch(arg2) {
case 0: switch(arg3) { // if milligram
case 0: answer = (arg1 * milligram) / milligram;
case 1: answer = (arg1 * milligram) / gram;
case 2: answer = (arg1 * milligram) / ounce;
case 3: answer = (arg1 * milligram) / pound;
}
case 1: switch(arg3) { // if gram
case 0: answer = (arg1 * gram) / milligram;
case 1: answer = (arg1 * gram) / gram;
case 2: answer = (arg1 * gram) / ounce;
case 3: answer = (arg1 * gram) / pound;
}
case 2: switch(arg3) { // if ounce
case 0: answer = (arg1 * ounce) / milligram;
case 1: answer = (arg1 * ounce) / gram;
case 2: answer = (arg1 * ounce) / ounce;
case 3: answer = (arg1 * ounce) / pound;
}
case 3: switch(arg3) { // if pound
case 0: answer = (arg1 * pound) / milligram;
case 1: answer = (arg1 * pound) / gram;
case 2: answer = (arg1 * pound) / ounce;
case 3: answer = (arg1 * pound) / pound;
}
} // end arg2 switch
return answer;
}
我的逻辑有些混乱，但我不知道在哪里。
任何帮助，将不胜感激。
你失踪了break声明：
case 0:
answer = (arg1 * milligram) / milligram;
break;
...
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