无法将正则表达式与 sed 匹配

我正在尝试匹配一个模式(\^|\~?)(\d|x|\*)+\.(\d|x|\*)+\.(\d|x|\*)+ with sed没有运气。 我正在运行的文件是这样的：

{
  "name": "something",
  "version": "0.0.1",
  "description": "some desc",
  "main": "gulpfile.js",
  "directories": {
    "test": "tests"
  },
  "dependencies": {
    "babel-polyfill": "^6.7.4",
    "babel-preset-es2015": "^6.6.0",
    "babel-preset-react": "^6.5.0",
    "gulp-clean": "^0.3.2",
    "jquery": "^2.1.4",
    "lodash": "^4.0.0",
    "moment": "^2.13.0",
    "moment-timezone": "^0.5.0",
    "radium": "^0.16.2",
    "react": "^15.1.0",
    "react-bootstrap-sweetalert": "^1.1.10",
    "react-dom": "^15.1.0",
    "react-timeago": "^2.2.1",
    "sprintf": "^0.1.5",
    "smoothscroll": "~0.2.2"
  },
  "devDependencies": {
    "babel": "^6.3.26",
    "babelify": "^7.2.0",
    "browserify": "~12.0.1",
    "console-stamp": "^0.2.0",
    "estraverse-fb": "^1.3.1",
    "gulp": "^3.9.0",
    "gulp-concat": "^2.6.0",
    "gulp-sass": "^2.1.1",
    "gulp-sourcemaps": "^1.6.0",
    "gulp-util": "^3.0.7",
    "lodash": "4.5.1",
    "lodash.assign": "^3.2.0",
    "lodash.isfunction": "^3.0.8",
    "lodash.reduce": "^4.3.0",
    "node-sass": "3.4.2",
    "react-bootstrap": "^0.29.4",
    "react-intl": "2.1.0",
    "reactify": "1.1.1",
    "sweetalert": "^1.1.3",
    "vinyl": "^1.1.0",
    "vinyl-buffer": "^1.0.0",
    "vinyl-source-stream": "^1.1.0",
    "watchify": "^3.4.0",
    "jsx-to-string": "~0.2.11"
  },
  "optionalDependencies": {
    "pkg-save": "~1.0.2"
  },
  "scripts": {
    "test": "echo \"Error: no test specified\" && exit 1"
  },
  "repository": {
    "type": "git",
    "url": "someurl"
  },
  "author": "authorname",
  "license": "MIT"
}

正如您在 regexr 中看到的，它匹配所需的模式（也匹配“版本”，但这是我稍后要解决的另一个问题）：http://regexr.com/3e324

我使用以下命令调用 sed：
cat package.json | sed 's/(\^|\~?)(\d|x|\*)+\.(\d|x|\*)+\.(\d|x|\*)+/Hello/g' -r

为了简洁起见，它输出类似的内容（即未经过滤的输入）：

...
"dependencies": {
    "babel-polyfill": "^6.7.4",
    "babel-preset-es2015": "^6.6.0",
    "babel-preset-react": "^6.5.0",
    "gulp-clean": "^0.3.2",
...

它应该用“Hello”替换所有数字。
我究竟做错了什么？
与坏标志有关（我已经尝试过/gm)
或者没有使用正确的正则表达式引擎（我正在传递-r使用扩展正则表达式的选项）？

虽然 POSIX 正则表达式支持一些命名字符类，例如[[:digit:]] and [[:alnum:]]，他们不支持速记类，例如\d and \w.

一些 GNU 扩展带来了速记类支持，但仅限于其中的少数几个，\w, \W, \s and \S根据正则表达式.info.

通过更换\d在你的正则表达式中[0-9]我能够转换你的文档。正则表达式变为(\^|\~?)([0-9]|x|\*)+\.([0-9]|x|\*)+\.([0-9]|x|\*)+， 或更好[~^]([0-9x*]+\.){2}[0-9x*]（感谢埃德·莫顿！）。

作为旁注，您的命令可以重写为以下内容，该命令不使用cat :

sed -E 's/[~^]([0-9x*]+\.){2}[0-9x*]/Hello/' package.json

正如 Matt 所指出的，你最好使用 JSON 解析器，例如jq.