Haskell 中的斐波那契数

大家好，我需要将我的 F# 代码更改为 Haskell 代码，但我对 Haskell 还很陌生，我不能这样做。我的代码只是从键盘读取数据，如果数据不是整数，则返回错误消息，然后计算 n 斐波那契数，然后写入list 之后将列表写入 txt 文件这是我的代码

open System
let rec fib n = 
    match n with
    |0->0
    |1->1
    |2->1
    |n->fib(n-1)+fib(n-2);;

let printFibonacci list = 
    for i=0 to (List.length list)-1 do
        printf "%d " (list.Item(i));;

let writeToFile list = 
    let file = System.IO.File.Create("C:\out2.txt")
    let mutable s =""
    let writer = new System.IO.StreamWriter(file)
    try
        for i=0 to (List.length list)-1 do
        s <- list.Item(i).ToString()
        writer.Write(s+" ")

    finally
        writer.Close()
        file.Dispose()
        printfn "Writed To File"


let mutable control = true
let mutable num = 0
while control do 
    try
    printfn "Enter a Number:" 

    num <- Convert.ToInt32(stdin.ReadLine()) 
    let listFibonacci = [for i in 0 .. num-1->fib(i)]
    printFibonacci(listFibonacci)
    printfn "\n%A"(listFibonacci)
    writeToFile(listFibonacci)
    control<-false
    with
        | :? System.FormatException->printfn "Number Format Exception";

Console.ReadKey true|>ignore

fib 0 = 0
fib 1 = 1
fib n = fib (n-1) + fib (n-2)

main = do putStrLn "Enter a number:"
          num <- readLn
          fibs = map fib [0..n]
          mapM' print fibs

然而，由于 haskell 很懒，所以有一种聪明的方法来定义所有斐波那契数的列表。由于您想要该列表的前缀，因此使用此定义更自然（也更有效）：

fibs = 0 : 1 : zipWith (+) fibs (tail fibs)

main = do putStrLn "Enter a number:"
          num <- readLn
          mapM' print (take n fibs)

编辑：写入文件而不是标准输出替换print with (\num -> appendFile "filename" (show num)) or (appendFile "filename" . show).