mssql 2个日期时间之间的30分钟时间间隔

我有以下查询，我想获取 2 个日期时间之间 30 分钟间隔的日期时间。基本上我得到了它，但它是有限的，如果时间差超过 24 小时，则不会返回所有结果。

例如：

@DateTime1 = 24/11/2016 18:00:00
@DateTime2 = 25/11/2016 06:00:00

结果：（格式为“dd-HH:mm”）

24-18:00
24-18:30
24-19:00
24-19:30
24-20:00
...
...
25-05:00
25-05:30
25-06:00

我尝试过的。

SELECT        number, DATEADD(MINUTE, number, @DateTime1) AS DateTimeLine, DATEPART(DAY, DATEADD(MINUTE, number, @DateTime1)) AS Days, DATEPART(MONTH, 
DATEADD(MINUTE, number, @DateTime1)) AS Months, DATEPART(YEAR, DATEADD(MINUTE, number, @DateTime1)) AS Years, DATEPART(HOUR, DATEADD(MINUTE,
number, @DateTime1)) AS Hours, DATEPART(MINUTE, DATEADD(MINUTE, number, @DateTime1)) AS Minute, CAST(DATEADD(MINUTE, number, @DateTime1) 
AS DATE) AS Date, CAST(DATEADD(MINUTE, number, @DateTime1) AS TIME) AS Time

FROM         master.dbo.spt_values

WHERE        (type = 'P') AND (DATEPART(MINUTE, DATEADD(MINUTE, number, @DateTime1)) = 30 OR DATEPART(MINUTE, DATEADD(MINUTE, number, @DateTime1)) = 0) AND (DATEADD(MINUTE, number, @DateTime1) <= @DateTime2)

ORDER BY number

统计表是处理此类事情的好方法。我保留一个视图以避免使用 spt_values。

create View [dbo].[cteTally] as

WITH
    E1(N) AS (select 1 from (values (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))dt(n)),
    E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
    E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
    cteTally(N) AS 
    (
        SELECT  ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
    )
select N from cteTally

那么你的代码也会变得非常简单。少量的数据数学，瞧。

declare @DateTime1 datetime = '2016/11/24 18:00:00'
    , @DateTime2 datetime = '2016/11/25 06:00:00'

select FORMAT(DATEADD(minute, (t.N - 1) * 30, @DateTime1), 'dd-HH:mm')
from cteTally t
where t.N <= (DATEDIFF(hour, @DateTime1, @DateTime2) * 2) + 1