我只有 1 个名为EMPLOYEE在我的数据库中包含以下 3 列：
Employee_Name, Employee_Salary, Department_ID
现在我必须选择每个工资高于其部门平均水平的员工。我怎么做？
我遇到的主要问题是，当将每个 Employee_Salary 与
SELECT AVG(department_ID) FROM employee GROUP BY Department_ID
内部队列的返回集返回多行。
我认为我需要执行连接操作，但我不知道如何执行。
请尝试以下查询
Select * from employee a where Employee_Salary > (select avg(Employee_Salary) from
employee b group by Department_ID having b.Department_ID = a.Department_ID)
or
Select * from employee a where Employee_Salary> (select avg(Employee_Salary) from
employee b where b.Department_ID = a.Department_ID group by Department_ID)
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