如何在 SQL 中选择重叠的日期范围

我有一个包含以下列的表： sID、开始日期和结束日期

一些值如下：

1   1995-07-28  2003-07-20 
1   2003-07-21  2010-05-04 
1   2010-05-03  2010-05-03 
2   1960-01-01  2011-03-01 
2   2011-03-02  2012-03-13 
2   2012-03-12  2012-10-21 
2   2012-10-22  2012-11-08 
3   2003-07-23  2010-05-02

我只想要结果中的第二行和第三行，因为它们是重叠的日期范围。

我尝试了这个，但它不会摆脱第一行。不确定我哪里出错了？

select a.sID from table a
inner join table b 
on a.sID = b.sID
and ((b.start_date between a.start_date and a.end_date)
and (b.end_date between a.start_date and b.end_date ))
order by end_date desc

我正在尝试在 SQL Server 中执行此操作

合理有效地做到这一点的一种方法是

WITH T1
     AS (SELECT *,
                MAX(end_date) OVER (PARTITION BY sID ORDER BY start_date) AS max_end_date_so_far
         FROM   YourTable),
     T2
     AS (SELECT *,
                range_start = IIF(start_date <= LAG(max_end_date_so_far) OVER (PARTITION BY sID ORDER BY start_date), 0, 1),
                next_range_start = IIF(LEAD(start_date) OVER (PARTITION BY sID ORDER BY start_date) <= max_end_date_so_far, 0, 1)
         FROM   T1)
SELECT SId,
       start_date,
       end_date
FROM   T2
WHERE  0 IN ( range_start, next_range_start ); 

如果你有一个索引(sID, start_date) INCLUDE (end_date)这可以通过单个有序扫描来执行工作。