好吧,盲目地使用正则表达式http://www.osix.net/modules/article/?id=586
var emailRegex =
new RegExp(
'([a-zA-Z0-9_\-\.]+)@((\[[0-9]{1,3}' +
'\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([a-zA-Z0-9\-]+\.' +
')+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)',
"gi");
var urlRegex =
new RegExp(
'((https?://)' +
'?(([0-9a-z_!~*\'().&=+$%-]+: )?[0-9a-z_!~*\'().&=+$%-]+@)?' + //user@
'(([0-9]{1,3}\.){3}[0-9]{1,3}' + // IP- 199.194.52.184
'|' + // allows either IP or domain
'([0-9a-z_!~*\'()-]+\.)*' + // tertiary domain(s)- www.
'([0-9a-z][0-9a-z-]{0,61})?[0-9a-z]\.' + // second level domain
'[a-z]{2,6})' + // first level domain- .com or .museum
'(:[0-9]{1,4})?' + // port number- :80
'((/?)|' + // a slash isn't required if there is no file name
'(/[0-9a-z_!~*\'().;?:@&=+$,%#-]+)+/?))',
"gi");
then
text.replace(emailRegex, "<a href='mailto::$1'>$1</a>");
and
text.replace(urlRegex, "<a href='$1'>$1</a>");
可能会工作