基本上我使用开发人员验证的身份来验证我的用户。即使此错误显示：
AWSiOSSDKv2 [详细] AWSURLResponseSerialization.m 行：87 |
-[AWSJSONResponseSerializer responseObjectForResponse:originalRequest:currentRequest:data:error:]
|响应正文：
[{"__type":"InvalidParameterException","message":"请提供
有效的公共提供者"}] 2015-10-20 17:50:19.251
BusyTime[56549:7365231] AWSiOSSDKv2 [错误] AWSCredentialsProvider.m
线路：435 | __73-[AWSCognitoCredentialsProvider
getCredentialsWithCognito:authenticated:]_block_invoke | getCredentialsWithCognito:authenticated:]_block_invoke |
GetCredentialsForIdentity 失败。错误是[错误
Domain=com.amazonaws.AWSCognitoIdentityErrorDomain 代码=7“
操作无法完成。
（com.amazonaws.AWSCognitoIdentityErrorDomain 错误 7。）”
UserInfo=0x7f9d9342dde0 {__type=InvalidParameterException，
message=请提供有效的公共提供者}]
尽管显示此错误，但我仍然返回我的 IdentityId 和 Token，并成功调用需要经过身份验证的权限才能调用的 lambda 方法。我相信这与我的刷新方法有关，但我不太确定。请帮我处理这个错误。
我的凭证提供者代码：
NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
[AWSLogger defaultLogger].logLevel = AWSLogLevelVerbose;
id<AWSCognitoIdentityProvider> identityProvider = [[BusytimeAuthenticated alloc] initWithRegionType:AWSRegionUSEast1
identityId:nil
identityPoolId:@"EXAMPLEPOOLID"
logins:@{@"login.busytimeapp": [defaults objectForKey:@"username"]}
providerName:@"login.busytimeapp"
];
credentialsProvider = [[AWSCognitoCredentialsProvider alloc] initWithRegionType:AWSRegionUSEast1
identityProvider:identityProvider
unauthRoleArn:nil
authRoleArn:nil];
configuration = [[AWSServiceConfiguration alloc] initWithRegion:AWSRegionUSEast1
credentialsProvider:self.credentialsProvider];
AWSServiceManager.defaultServiceManager.defaultServiceConfiguration = configuration;
[[credentialsProvider refresh] continueWithBlock:^id(BFTask *task){
[self testAuth];
return nil;
}];
我的刷新方法：
- (BFTask *)refresh {
NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
if (![self authenticatedWithProvider]) {
return [super getIdentityId];
}else{
NSDictionary *post = [[NSDictionary alloc] initWithObjectsAndKeys:
[defaults objectForKey:@"username"], @"username",
[defaults objectForKey:@"password"], @"password",
nil];
NSError *error;
NSData *postData = [NSJSONSerialization dataWithJSONObject:post options:0 error:&error];
NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:@"SOMEURL"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];
NSURLSession *session = [NSURLSession sessionWithConfiguration:[NSURLSessionConfiguration defaultSessionConfiguration]];
__block BOOL isLogged = false;
[[session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
NSDictionary *newJSON = [NSJSONSerialization JSONObjectWithData:data
options:0
error:&error];
isLogged = true;
if(!newJSON){
NSLog(@"DID NOT AUTHENTICATE");
}else{
self.identityId = [newJSON objectForKey:@"IdentityId" ];
self.token = [newJSON objectForKey:@"Token" ];
NSLog(@"Result: %@", newJSON);
}
}] resume];
return [super getIdentityId];
}
return [super getIdentityId];
}
这里的问题是您将登录映射中的登录提供程序名称作为键传递。您无法对开发人员验证的身份执行此操作。
相反，您应该使用 Cognito 身份提供商名称，cognito-identity.amazonaws.com，在地图上，就像它在文档。这应该可以解决您的异常问题。
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