我使用 python 编写一个电报机器人远程遥控API。我现在陷入了这样的境地:我想发送直接来自 URL 的图片,而不将其存储在本地。Telepot提供以下发送照片的说明:
>>> f = open('zzzzzzzz.jpg', 'rb') # some file on local disk
>>> response = bot.sendPhoto(chat_id, f)
现在我正在使用
f = urllib2.urlopen('http://i.imgur.com/B1fzGoh.jpg')
bot.sendPhoto(chat_id, f)
这里的问题是urllib2.urlopen('url')
为我提供类似文件的对象,例如:
<addinfourl at 140379102313792 whose fp = <socket._fileobject object at 0x7fac8e86d750>>
不喜欢open('myFile.jpg', 'rb')
文件对象,例如:
<open file 'app-root/runtime/repo/myImage.jpg', mode 'rb' at 0x7fac8f322540>
如果我在 sendPhoto() 中发送类似文件的对象,则会收到以下错误:
回溯(最近一次调用最后一次):
[Wed Feb 10 06:21:09 2016] [error] File "/var/lib/openshift/56b8e2787628e1484a00013e/python/virtenv/lib/python2.7/site-packages/telepot/__init__.py", line 340, in handle
[Wed Feb 10 06:21:09 2016] [error] callback(update['message'])
[Wed Feb 10 06:21:09 2016] [error] File "/var/lib/openshift/56b8e2787628e1484a00013e/app-root/runtime/repo/moviequiz_main.py", line 35, in handle
[Wed Feb 10 06:21:09 2016] [error] response = bot.sendPhoto(chat_id, gif)
[Wed Feb 10 06:21:09 2016] [error] File "/var/lib/openshift/56b8e2787628e1484a00013e/python/virtenv/lib/python2.7/site-packages/telepot/__init__.py", line 230, in sendPhoto
[Wed Feb 10 06:21:09 2016] [error] return self._sendFile(photo, 'photo', p)
[Wed Feb 10 06:21:09 2016] [error] File "/var/lib/openshift/56b8e2787628e1484a00013e/python/virtenv/lib/python2.7/site-packages/telepot/__init__.py", line 226, in _sendFile
[Wed Feb 10 06:21:09 2016] [error] return self._parse(r)
[Wed Feb 10 06:21:09 2016] [error] File "/var/lib/openshift/56b8e2787628e1484a00013e/python/virtenv/lib/python2.7/site-packages/telepot/__init__.py", line 172, in _parse
[Wed Feb 10 06:21:09 2016] [error] raise BadHTTPResponse(response.status_code, response.text)
[Wed Feb 10 06:21:09 2016] [error] BadHTTPResponse: (414, u'<html>\\r\\n<head><title>414 Request-URI Too Large</title></head>\\r\\n<body bgcolor="white">\\r\\n<center><h1>414 Request-URI Too Large</h1></center>\\r\\n<hr><center>nginx/1.9.1</center>\\r\\n</body>\\r\\n</html>\\r\\n')
有一个解决方案这里提供了不同的电报机器人项目他们发送到的地方urllib2.urlopen('url').read()
回到 telegram,但就我而言,这会产生与没有 .read() 相同的错误。
如何从 url 获取文件作为文件对象(最好是不将其保存在本地)?
或者如何从 urlopen() 提供的“类文件对象”中获取“文件对象”?
谢谢你的帮助 :)