从 EMPLOYEE 表中，我想对记录数量（雇用的员工）进行分组，并且还有每天的运行总数。
输入的格式是这样的：
rownum Hired_date_time
1 1/10/2012 11:00
2 1/10/2012 13:00
3 20/11/2012 10:00
4 20/11/2012 15:00
5 20/11/2012 16:00
6 30/12/2012 1:00
所需的输出：
Hired_date.......Hired_per_day.........TOTAL_number_of_employees
1/10/2012 ...................2 ........2
20/11/2012 ..................3 ........5
30/12/2012 ..................1 ....... 6
每天分组没有问题：
select trunc(Hired_date_time) as "Hired_date" ,
count(*) as "Hired_per_day"
from employee
group by trunc(Hired_date_time)
order by trunc(Hired_date_time);
Question
select trunc(hired),
count(*) hired_today,
sum(count(*)) over (order by trunc(hired)) as running_total
from emp
group by trunc(hired)
http://sqlfiddle.com/#!4/4bd36/9
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