首先 - 链接不起作用。其次:根据 HTTP 请求的输出,可以有 2 种方法。
如果输出是文件,您可以使用以下代码:
Sub DownloadFile(url As String, filePath As String)
Dim WinHttpReq As Object, attempts As Integer
attempts = 3
On Error GoTo TryAgain
TryAgain:
attempts = attempts - 1
Err.Clear
If attempts > 0 Then
Set WinHttpReq = CreateObject("Microsoft.XMLHTTP")
WinHttpReq.Open "GET", url, False
WinHttpReq.send
If WinHttpReq.Status = 200 Then
Set oStream = CreateObject("ADODB.Stream")
oStream.Open
oStream.Type = 1
oStream.Write WinHttpReq.responseBody
oStream.SaveToFile filePath, 2 ' 1 = no overwrite, 2 = overwrite
oStream.Close
End If
End If
End Sub
如果输出是简单的文本 HTML 响应,您可以将输出保存到文件中
Function GetXMLHTTPResult(url As String)
Dim XMLHTTP As Object, attempts As Integer
attempts = 3
On Error GoTo TryAgain
TryAgain:
attempts = attempts - 1
Err.Clear
If attempts > 0 Then
Set XMLHTTP = CreateObject("MSXML2.serverXMLHTTP")
XMLHTTP.Open "GET", url, False
XMLHTTP.setRequestHeader "Content-Type", "text/xml"
XMLHTTP.setRequestHeader "Cache-Control", "no-cache"
XMLHTTP.setRequestHeader "Pragma", "no-cache"
XMLHTTP.setRequestHeader "User-Agent", "Mozilla/5.0 (Windows NT 6.1; rv:25.0) Gecko/20100101 Firefox/25.0"
XMLHTTP.send
GetXMLHTTPResult = XMLHTTP.ResponseText
End If
End Function
Sub SaveFile(url)
res = GetXMLHTTPResult(url)
Open "C:\res.txt" For Output As #1
Write #1, res
Close #1
End Sub