use $(this).serializeArray()
代替$(this).serialize()
参考:-https://api.jquery.com/serializeArray/
两者的区别:-https://stackoverflow.com/a/10430571/4248328
您需要执行以下操作:-
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id='contact'>
<input type='text' name='modal_name' id='modal_name' />
<input type='email' name='modal_email' id='modal_email' />
<textarea name='modal_message' id='modal_message'></textarea>
<input type="submit" value = "submit">
</form>
<script type="text/javascript">
$('#contact').on('submit', function(e) {
e.preventDefault();
if (modal_name && modal_email && modal_message) {
var data = $(this).serializeArray();
data.push({name: 'action', value: 'send_message'});
$.post('query.php', data, function(response) {
$('.modal').append(response);
});
}
});
</script>
在 PHP 中:-
<?php
if(!empty($_POST)){
echo "<pre/>";print_r($_POST);
}
?>
它将输出如下:-
<pre/>Array
(
[modal_name] => sdsadsa
[modal_email] => [email protected]
[modal_message] => sadada
[action] => send_message
)
注意:- 如果您想使用serialize()
然后才像下面这样:-
<script type="text/javascript">
$('#contact').on('submit', function(e) {
e.preventDefault();
if (modal_name && modal_email && modal_message) {
var data = $(this).serialize()+ '&action=send_message';
$.post('query.php', data, function(response) {
$('.modal').append(response);
});
}
});
</script>