<body>
<FORM NAME="Calculator">
<TABLE BORDER=4>
<TR>
<TD>
<input type="text" name="Input" Size="22" value="">
<br>
</TD>
</TR>
<TR>
<TD>
<INPUT TYPE="button" NAME="one" VALUE="1" class ="digit" >
<INPUT TYPE="button" NAME="two" VALUE="2" class ="digit" >
<INPUT TYPE="button" NAME="three" VALUE="3" class ="digit" >
<INPUT TYPE="button" NAME="plus" VALUE="+" class ="operand">
<br>
<INPUT TYPE="button" NAME="four" VALUE="4" class ="digit">
<INPUT TYPE="button" NAME="five" VALUE="5" class ="digit">
<INPUT TYPE="button" NAME="six" VALUE="6" class ="digit">
<INPUT TYPE="button" NAME="minus" VALUE="-" class="operand">
<br>
<INPUT TYPE="button" NAME="seven" VALUE="7" class ="digit">
<INPUT TYPE="button" NAME="eight" VALUE="8" class ="digit">
<INPUT TYPE="button" NAME="nine" VALUE="9" class ="digit">
<INPUT TYPE="button" NAME="times" VALUE="*" class ="operand">
<br>
<INPUT TYPE="button" NAME="clear" VALUE="c" class ="special">
<INPUT TYPE="button" NAME="zero" VALUE="0" class ="digit">
<INPUT TYPE="button" NAME="Execute" VALUE="=" class ="solve">
<INPUT TYPE="button" NAME="div" VALUE="/" class ="operand">
<br>
</TD>
</TR>
</TABLE>
</FORM>
<script type = "text/javascript" src="C:\Users\Quonn\Desktop\QBJS\calculatorjs.js">
</script>
</body>
我正在构建一个可配置的计算器,但我有一些符合我的逻辑/让它完全按照我想要的方式运行。我有两个问题。
问题#1:我怎样才能改变我的逻辑,以便我可以取代“邪恶的评估”?
var timer;
document.onclick = function(x) {
var info = x.target;
clearTimeout(timer);
timer= setTimeout(function(){addDigit(x);},200);
}
问题2:如何更改此函数中的逻辑,以便在显示计算结果后,为下一个计算输入的第一个数字不只是连接到上一个计算的结果?
function addDigit(x){
if (x.target.className === "digit" || x.target.className ==="operand") {
document.Calculator.Input.value += "" + x.target.value;
}
else if (x.target.className === "solve") {
result = eval(document.Calculator.Input.value);
document.Calculator.Input.value = result;
}
else {
document.Calculator.Input.value = "";
}
}
您正在连接字符串。你应该看看parseInt / 解析浮点型;注意基数,否则 JavaScript 会尝试猜测它......
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