当前的 Ruby 方法是通过 super 调用的吗？

在运行时的方法中，有没有办法知道该方法是否已被调用super在子类中？例如。

module SuperDetector
  def via_super?
    # what goes here?
  end
end

class Foo
  include SuperDetector

  def bar
    via_super? ? 'super!' : 'nothing special'
  end
end

class Fu < Foo
  def bar
    super
  end
end

Foo.new.bar # => "nothing special"
Fu.new.bar  # => "super!"

我怎么能写via_super?，或者，如果有必要，via_super?(:bar)?

可能有更好的方法，但总体思路是Object#instance_of?仅限于当前类，而不是层次结构：

module SuperDetector
  def self.included(clazz)
    clazz.send(:define_method, :via_super?) do
      !self.instance_of?(clazz)
    end
  end
end

class Foo
  include SuperDetector

  def bar
    via_super? ? 'super!' : 'nothing special'
  end
end

class Fu < Foo
  def bar
    super
  end
end

Foo.new.bar # => "nothing special"
Fu.new.bar  # => "super!"

---

However, note that this doesn't require explicit super in the child. If the child has no such method and the parent's one is used, via_super? will still return true. I don't think there is a way to catch only the super case other than inspecting the stack trace or the code itself.