LineChart FX - 删除实线

我有一个关于图表 LineChart JavaFX 的好奇问题。

I have this graph: dots forming a "jump" on the X axis (as shown by the two red points I scored) and therefore JavaFX draws me the line between these two points. How do I remove that line between each "jump"?

我发布代码：

public class ControllerIndividua {

    public static void plotIndividuaFull(String path, Stage stage, String name) {
        final NumberAxis xAxisIntensity = new NumberAxis(); //Dichiarazione asseX
        final NumberAxis yAxisIntensity = new NumberAxis();//Dichiarazione asseY

        DetectionS1.countS1();

        //Dichiarazione del tipo di grafico
        final LineChart<Number, Number> lineChartIntensity = new LineChart<Number, Number>(xAxisIntensity,yAxisIntensity);

        ArrayList<Double> extractedData; //Lista dei valori dello dell' intensità
        ArrayList<Double> extractedTime; //Lista del tempo
        ArrayList<Double> extractedS1; //Lista del tempo
        ArrayList<Double> extractedS1Time; //Lista del tempo

        //Gestione e settaggio del grafico
        lineChartIntensity.getData().clear();

        try {
            //Popolamento delle liste
            extractedTime = IntensityExtractor.pointsTime();
            extractedData = IntensityExtractor.pointsIntensity();
            extractedS1 = DetectionS1.S1pitch();
            extractedS1Time = DetectionS1.pointsS1Time();
            XYChart.Series<Number, Number> series = new XYChart.Series<Number, Number>();
            XYChart.Series<Number, Number> seriesS1 = new XYChart.Series<Number, Number>(); //Creazione seconda serie
            series.setName("Intensità di:\t" + name.toUpperCase());

            for (int j = 0; j < extractedS1.size(); j++) {
                seriesS1.getData().add(new XYChart.Data<Number, Number>(extractedS1Time.get(j), extractedS1.get(j)));
                lineChartIntensity.getStyleClass().add("CSSintensity");
            }

            //Creazione finestra e stampa del grafico
            Scene scene = new Scene(lineChartIntensity, 1000, 600);
            lineChartIntensity.getData().addAll(series,seriesS1);
            scene.getStylesheets().add("application/application.css");
            stage.setScene(scene);
            stage.show();
        } catch (java.lang.Exception e) {
            e.printStackTrace();
        }
    }
}

有人也对我该怎么做有一点想法吗？

谢谢大家。

这是一个老问题，有一个公认的答案，但我遇到了它并且很好奇。我想知道是否可以在LineChart（至少无需创建自定义图表实现）。事实证明是有的。该解决方案有点老套且脆弱。它涉及到获得Path通过使用XYChart.Series.getNode()并操纵列表PathElements。下面的代码给出了一个例子：

import javafx.application.Application;
import javafx.application.Platform;
import javafx.scene.Scene;
import javafx.scene.chart.LineChart;
import javafx.scene.chart.NumberAxis;
import javafx.scene.chart.XYChart;
import javafx.scene.layout.StackPane;
import javafx.scene.shape.LineTo;
import javafx.scene.shape.MoveTo;
import javafx.scene.shape.Path;
import javafx.stage.Stage;

public class Main extends Application {

    @Override
    public void start(Stage primaryStage) {
        LineChart<Number, Number> chart = new LineChart<>(new NumberAxis(), new NumberAxis());
        chart.getXAxis().setLabel("X");
        chart.getYAxis().setLabel("Y");
        chart.setLegendVisible(false);
        chart.getData().add(new XYChart.Series<>());

        for (int x = 0; x <= 10; x++) {
            chart.getData().get(0).getData().add(new XYChart.Data<>(x, Math.pow(x, 2)));
        }

        /*
         * Had to wrap the call in a Platform.runLater otherwise the Path was
         * redrawn after the modifications are made.
         */
        primaryStage.setOnShown(we -> Platform.runLater(() -> {
            Path path = (Path) chart.getData().get(0).getNode();
            LineTo lineTo = (LineTo) path.getElements().get(8);
            path.getElements().set(8, new MoveTo(lineTo.getX(), lineTo.getY()));
        }));

        primaryStage.setScene(new Scene(new StackPane(chart), 500, 300));
        primaryStage.setTitle("LineChart Gap");
        primaryStage.show();
    }

}

该代码产生以下结果：

这是可能的，因为ObservableList of PathElements 似乎是一个MoveTo后面跟着一堆LineTos。我简单地选了一个LineTo并将其替换为MoveTo到相同的坐标。我还没弄清楚哪个索引LineTo与哪个匹配XYChart.Data，然而，并选择了8随机的例子。

该解决方案存在几个问题。第一个也是明显的一个是，这依赖于内部实现LineChart。第二个是真正的脆弱性的来源。对数据的任何更改，无论是轴的值范围、图表的宽度或高度，还是几乎anything导致图表重新绘制本身将导致Path重新计算和重新绘制。这意味着如果您使用此解决方案，则必须重新应用修改每次图表会自行重绘。