Android - 滑动手势出现问题

我正在尝试在我的应用程序中实现滑动手势。我已经编写了几乎所有代码，但它不起作用。

这是我的活动中的代码：

// Swipe detector
gestureDetector = new GestureDetector(new SwipeGesture(this));
gestureListener = new OnTouchListener() {
    public boolean onTouch(View v, MotionEvent event)
    {
        Log.e("", "It works");
        return gestureDetector.onTouchEvent(event);
    }
};

LinearLayout root = (LinearLayout) findViewById(R.id.rules_root);
root.setOnTouchListener(gestureListener);

当我触摸屏幕时，会显示 logcatit works.

这是我的班级代码SwipeGesture:

public class SwipeGesture extends SimpleOnGestureListener
{
    private static final int SWIPE_MIN_DISTANCE = 120;
    private static final int SWIPE_MAX_OFF_PATH = 250;
    private static final int SWIPE_THRESHOLD_VELOCITY = 200;

    private Activity activity;

    public SwipeGesture(Activity activity)
    {
        super();
        this.activity = activity;
    }

    @Override
    public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY)
    {
        Log.e("", "Here I am");
        try
        {
            if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH) return false;
            if(e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY)
            {
                if ( ((TabActivity) activity.getParent()).getTabHost() != null )
                {
                    TabHost th = ((TabActivity) activity.getParent()).getTabHost();
                    th.setCurrentTab(th.getCurrentTab() - 1);
                }
                else
                {
                    activity.finish();
                }
                Log.e("", "Swipe left");
            }
            else if (e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY)
            {
                if ( ((TabActivity) activity.getParent()).getTabHost() != null )
                {
                    TabHost th = ((TabActivity) activity.getParent()).getTabHost();
                    th.setCurrentTab(th.getCurrentTab() + 1);
                }
                Log.e("", "Swipe right");
            }
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
        return false;
    }
}

线路Log.e("", "Here I am");永远不会显示。所以我认为 onFling 方法永远不会被调用。

关于为什么这行不通的任何想法？

Thanks.

Regards.

V.

在您的 SimpleOnGestureListener 中，覆盖 onDown 以注册您的手势。它可以只返回 true，但必须这样定义..

@Override
    public boolean onDown(MotionEvent e) {
            return true;
    }

....请参阅此链接..以及答案下面的评论..