我需要在 PHP 中删除空白行(带有空格或绝对空白)。我使用这个正则表达式,但它不起作用:
$str = ereg_replace('^[ \t]*$\r?\n', '', $str);
$str = preg_replace('^[ \t]*$\r?\n', '', $str);
我想要的结果是:
blahblah
blahblah
adsa
sad asdasd
will:
blahblah
blahblah
adsa
sad asdasd
// New line is required to split non-blank lines
preg_replace("/(^[\r\n]*|[\r\n]+)[\s\t]*[\r\n]+/", "\n", $string);
上面的正则表达式表示:
/(^[\r\n]*|[\r\n]+)[\s\t]*[\r\n]+/
1st Capturing group (^[\r\n]*|[\r\n]+)
1st Alternative: ^[\r\n]*
^ assert position at start of the string
[\r\n]* match a single character present in the list below
Quantifier: Between zero and unlimited times, as many times as possible, giving back as needed [greedy]
\r matches a carriage return (ASCII 13)
\n matches a fine-feed (newline) character (ASCII 10)
2nd Alternative: [\r\n]+
[\r\n]+ match a single character present in the list below
Quantifier: Between one and unlimited times, as many times as possible, giving back as needed [greedy]
\r matches a carriage return (ASCII 13)
\n matches a fine-feed (newline) character (ASCII 10)
[\s\t]* match a single character present in the list below
Quantifier: Between zero and unlimited times, as many times as possible, giving back as needed [greedy]
\s match any white space character [\r\n\t\f ]
\tTab (ASCII 9)
[\r\n]+ match a single character present in the list below
Quantifier: Between one and unlimited times, as many times as possible, giving back as needed [greedy]
\r matches a carriage return (ASCII 13)
\n matches a fine-feed (newline) character (ASCII 10)
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