我正在构建一个 Chrome 扩展程序，希望在用户单击 Chrome 中的浏览器操作图标时显示弹出窗口并运行脚本。
我可以通过将 '"default_popup": "popup.html"' 放入 manifest.json 来实现弹出窗口。但是，当我这样做时，background.js 似乎没有运行。当我删除 '"default_popup": "popup.html"' 时，background.js 似乎会运行。
如何同时显示弹出窗口和运行脚本？
清单.json
{
"manifest_version": 2,
"name": "Typo Blaster",
"description": "Blast away typos and make the internet a safer place for the kids.",
"version": "0.1",
"browser_action": {
"default_icon": "icon.png",
"default_title": "Blast the typo!",
"default_popup": "popup.html"
},
"permissions": [
"activeTab"
],
"background": {
"scripts": ["background.js"],
"persistent": false
},
"icons": { "16": "icon16.png",
"48": "icon48.png",
"128": "icon128.png" }
}
弹出窗口.html
<!doctype html>
<html>
<head>
<title>Typo Blaster</title>
<style>
body {
min-width: 357px;
overflow-x: hidden;
}
img {
margin: 5px;
border: 2px solid black;
vertical-align: middle;
width: 75px;
height: 75px;
}
</style>
<script src="popup.js"></script>
</head>
<body>
<h1>Got it!</h1>
</body>
</html>
背景.js
chrome.browserAction.onClicked.addListener(function(tab) {
// No tabs or host permissions needed!
console.log('Turning ' + tab.url + ' red!');
chrome.tabs.executeScript({
code: 'document.body.style.backgroundColor="red"'
});
});
alert('hello ' + document.location.href);
